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cluponka [151]
3 years ago
6

Identify the expression equivalent to 4(x + x + 7) − 2x + 8 − 4 by substituting x = 1 and x = 2. 6x + 11 3(x + 7) 2(3x + 16) 3x

+ 16
Mathematics
1 answer:
sveta [45]3 years ago
5 0

2(3x+16)

Step-by-step explanation:

Identify the expression equivalent to 4(x + x + 7) − 2x + 8 − 4

4(x + x + 7) − 2x + 8 − 4

When x=1 , the expression becomes 4(1+1+7)-2(1)+8-4=38

When x=2 , the expression becomes 4(2+2+7)-2(1)+8-4=44

Plug in x=1  and check with each expression

6x + 11 =6(1) +11= 16

3(x + 7) = 3(1+7)= 3(8)= 24

2(3x + 16) = 2(3(1)+16)= 38 , we got same answer when x=1, now check with x=2

2(3x + 16) = 2(3(2)+16)= 44

3x + 16= 3+16= 19

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mars1129 [50]

Answer:

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  • 5.36 km (per side hash marks)

Step-by-step explanation:

Going by the angle indicators, the ratios of corresponding sides of the similar triangles are ...

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  x = 2000·6/5 = 2400 . . . . yards

Then the distance of interest is ...

  (2400 yd + 4200 yd)×(0.0009144 km/yd) = 6.6×.9144 km

  = 6.03504 km ≈ 6.04 km

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Going by the red hash marks, the ratios of corresponding sides of the similar triangles are ...

  x/2000 = 3500/4200

  x = 2000·(5/6) = 5000/3 . . . . yards

Then the distance of interest is ...

  (5000/3 + 4200) yd × 0.0009144 km/yd ≈ 5.36 km

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<em>Comment on the figure</em>

The usual geometry here is that the outside legs (opposite the vertical angles) are parallel, meaning that the angle indicators are the correct marks. It is possible, but unusual, for the red hash marks to be correct and the angle indicators to be mismarked. The red hash marks seem tentatively drawn, so seem like they're more likely to be the incorrect marks.

7 0
3 years ago
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(Small sample confidence intervals for a population mean) suppose you are taking a sampling of 15 measurements. you find that x=
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Answer:

The 99% confidence interval is  71.67 < \mu < 78.33

Step-by-step explanation:

From the question we are told that

     The sample  size  is  n  =  15

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 Given that confidence is  99%  then the level of significance is mathematically represented as

              \alpha  =  100 -  99

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Next we obtain the critical values of  \frac{ \alpha }{2} from the normal distribution table

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            E =  Z_{\frac{ \alpha }{2} } *  \frac{ s}{ \sqrt{n} }

=>         E =  2.58  *  \frac{ 5}{ \sqrt{15} }

=>         E =  3.3307

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=>          75 -  3.3307 <  \mu

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3 0
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madam [21]
39.2 is what percent p of 112

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guapka [62]
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