Solve (2x + 3) - (9x

The equation of the line is 3y+2x=12 . what is the slope of the line perpendicular to this equation?

Ket [755]

The slope
$\frac{3}{2}$

6 0

3 years ago

You discover that you are over serving a dish because customers keep taking a third of it home. If the dish requires 4 ingredien

devlian [24]

Answer:

4 parts

Step-by-step explanation:

If the total number of parts is 12 and you want to reduce the dish to two-thirds its current size, the number of parts that will be reduced is (1 - 2/3) = 1/3

To reduce 1/3 of the 12 parts, you need to multiply 12 by 1/3 to know how many parts is that:

12 * 1/3 = 12/3 = 4

You need to subtract 4 parts. If you have 4 ingredients, you can remove 1 part of each, so each ingredient now will have 2 parts.

5 0

4 years ago

In the situation, simple interest is calculated yearly. How much interest was earned? Drag and drop the answer into the box. Pri

ad-work [718]

I = PRT
P = 8000
T = 4
R = 12%...turn to decimal...0.12
now we sub
I = (8000)(0.12)(4)
I = 3840 <==

7 0

3 years ago

a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade

son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

$P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})$

$P(at least 1 dull blade)=1-0.2931$

P(at least 1 dull blade)=0.7068

5 0

3 years ago

78 : 120 :: ? : 66 please give answer with explanation

yawa3891 [41]

Step-by-step explanation:

Method 1:

Given that:

78 : 120 :: ? : 66

Here,

Product of extremes = 78 and 66

Product of means = 120 and ?

so,

(78*66) = (120 * ?)

⇛5148 = 120 * ?

⇛5148 = 120?

⇛120? = 5148

Shift the number 120 from LHS to RHS, changing it's sign.

⇛? = 5148/120

Therefore, (?) = 42.9

Method 2:

78 : 120 :: ? : 66

Convert each ratio into fraction.

⇛78/120 = ?/66

On applying cross multiplication then

since, (a/b) = (c/d) ⇛cd = ad

Where, a = 78, b = 120, c = ? and d = 66

Now,

⇛(120)? = (78)66

⇛120? = 5148

⇛(?) = 5148/120

Therefore, (?) = 42.9

Answer: Hence the value of (?) for the given problem is 42.9.

Verification:

Check whether the value of (?) is true or false.

78 : 120 :: ? : 66

Substitute the value of (?).

⇛78:120 = 42.9:66

Product of extremes should be equal to product of means.

Product of extremes:- 78*66 = 5148

Product of means:- 120*42.9 = 5148

⇛5148 = 5148

LHS = RHS

Hence, verified.

4 0

2 years ago

Solve (2x + 3) - (9x - 3)