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bazaltina [42]
3 years ago
5

Can somebody please balance this !?!

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
4 0
\mathrm{CO}_2 has 2 oxygens for every carbon. \mathrm{CO} will contribute one of each for every molecule. You then have to have an even multiple of \mathrm{CO} molecules to not end up with an odd number of oxygens.

So if you take 2\mathrm{CO}, you should end up with 2 carbons on the RHS. 2\mathrm{CO}_2 then has 4 oxygens. 2 of them are already accounted for, so you just need one \mathrm O_2 to balance out the reaction.

1\mathrm O_2+2\mathrm{CO}\Rightarrow2\mathrm{CO}_2
Marta_Voda [28]3 years ago
3 0
O2 + 2CO = 2CO2. That should be it
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Professor Lam is grading papers in the teachers' lounge. He has already finished grading 6 assignments, and is grading 4 more as
Delvig [45]

Answer:

Step-by-step explanation: If Professor Lam grades 4 papers per hour, in 11 hours he will graded 44 papers. (11 x 4= 44). He had previously graded 6 papers giving him a total of 50 papers graded. His assistant can grade 5 papers per hour, thus it would take him 10 hours to grade the same amount of papers as Professor Lam. (10 x 5= 50) Thus: 11 hours Professor Lam 50 papers graded; 10 hours his assistant 50 papers graded.

3 0
2 years ago
Please find X when x÷20=5
tia_tia [17]
X=100 because 20 X 5 is 100
6 0
3 years ago
Read 2 more answers
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
What is the end behavior of the function f(x)=−1/4x^2?
ki77a [65]

Answer:

As x approaches infinity, f(x) approaches negative infinity

As x approaches negative infinity, f(x) approaches negative infinity

Step-by-step explanation:

Because the function goes in the downward direction on both sides, it would be negative infinity for both.

It's basically saying, as the x values go towards the positives, the y values go towards the negatives

and as the x values go towards the negatives, the y values go towards the negatives.

3 0
1 year ago
The area of a triangle is 45.5 cm2 and the base is 10 cm.
blondinia [14]
The area of a triangle is A=1/2b*h
You have the base (b) and you have the area (A)
So, if you plug in what you know, you get this:
45.5=1/2*10*h
Simplify it:
45.5=5h

Now solve for h
Divide by 5 to get h alone:
9.1=h

Your height is 9.1cm
Hope this helps :)
3 0
3 years ago
Read 2 more answers
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