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bazaltina [42]
3 years ago
5

Can somebody please balance this !?!

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
4 0
\mathrm{CO}_2 has 2 oxygens for every carbon. \mathrm{CO} will contribute one of each for every molecule. You then have to have an even multiple of \mathrm{CO} molecules to not end up with an odd number of oxygens.

So if you take 2\mathrm{CO}, you should end up with 2 carbons on the RHS. 2\mathrm{CO}_2 then has 4 oxygens. 2 of them are already accounted for, so you just need one \mathrm O_2 to balance out the reaction.

1\mathrm O_2+2\mathrm{CO}\Rightarrow2\mathrm{CO}_2
Marta_Voda [28]3 years ago
3 0
O2 + 2CO = 2CO2. That should be it
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