A pack of gum costs 50 cents. That is 4 cents less than four times what the pack cost 15 years ago.

Mathematics

1 answer:

alisha [4.7K]2 years ago

7 0

15 years ago pack
= 4 x 0.50 + 0.04
= 2.04

15 years ago, pack costed $2.04

Hope this helps. - M

You might be interested in

Last year 190 student attended the spring dance and the total cost was 1250. Two years ago 175 people attended and the total cos

kondor19780726 [428]

Unit cost of a ticket = Income from ticket sales / number of tickets sold:

$1250
--------------- = $6.58 per ticket
190 tickets

Again:

$1175
--------------- = $6.71
175 tickets

While ticket prices do change (usually increase) from year to year, it's unusual to see such a situation here.

Don't have any guidelines by which to determine the "fixed cost of a ticket".

If we use the cost of a ticket of 2 years ago ($6.58/ticket), then the income from the sale of 225 tickets this year would be ($6.58/ticket)(225 tickets), or $1480.50.

6 0

3 years ago

Less than 100 students want to start at 9:00 am is it a random sampling or a population inferences

quester [9]

Population inferences. Step-by-step explanation:

5 0

2 years ago

The variables x and y vary directly. Use the given values to write an equation that relates x and y: x = 4, y = -16

Gnesinka [82]

Vary Directly: y = k*x

Vary Inversely: y = k/x

Because x and y vary directly, our equation will look like the first one.

y = k*x

With the inputted values:

-16 = k * 4

Now, to find k, isolate the variable

k = -16/4 = -4

Your final equation will then look like this:

y = -4 * x

4 0

3 years ago

on a deposit of $4,000 that earns 8% compound interest compounded annually how much will you have after 2 years

NikAS [45]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=4000\left(1+\frac{0.08}{1}\right)^{1\cdot 2}\implies A=4000(1.08)^2\implies A=4665.6$

7 0

3 years ago

Write an equation expression with positive exponents only.

svlad2 [7]

Answer:

x^4 * (1/y^2)

Step-by-step explanation:

A negative exponent is just the reciprocal of the positive version of the exponent.

4 0

2 years ago