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2 years ago

What is the value of x? Round to the nearest tenth(1 decimal place)

Mathematics

1 answer:

liraira [26]2 years ago

6 0

Answer:

x ≈ 15.0 ft

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Trigonometry

tan∅ = opposite over adjacent

Step-by-step explanation:

Step 1: Define

Angle = 28°

Opposite leg of angle = 8 ft

Adjacent leg of angle = x ft

Step 2: Find x

Substitute: tan28° = 8/x
Multiply x on both sides: xtan28° = 8
Divide tan28° on both sides: x = 8/tan28°
Evaluate: x = 15.0458
Round: x ≈ 15.0 ft

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$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Base of a cube is a square, and in the given figure it's stated that the measure of each side is " x " ft

Therefore it's Area is equal to : -

$side \times side$

$x \times x$

${x}^{2}$

Now, since it's Area is given as 1/4 ft², let's equate the Areas to find the measure of each side ~

that is ~

${x}^{2} = \dfrac{1}{4}$

$x = \sqrt{ \dfrac{1}{2} \times \dfrac{1}{2} }$

$x = \dfrac{1}{2} \: \: feet$

It's time to find the volume of cube that is ~

$(side) {}^{3}$

So, let's plug the value of side length (1/2 ft)

Volume is equal to ~

${ \bigg(\dfrac{1}{2} \bigg) }^{3}$

$\dfrac{1}{8} \: \: ft {}^{3}$

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What is the value of x? Round to the nearest tenth(1 decimal place)​

What is the value of x? Round to the nearest tenth(1 decimal place)