Answer:
(x+y)/xy or (1/x + 1/y) portion of the leaves
Step-by-step explanation:
Let the total work done to rake the leaves be a for representation.
Thus,
given Maya takes x minutes to rake the leaves
thus,
work done by may in x minutes = a
dividing both side by x
work done by maya in x/x = 1 minutes = a/x
similarly
given Calra takes y minutes to rake the leaves
thus,
work done by may in y minutes = a
dividing both side by y
work done by maya in y/y = 1 minutes = a/y
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Total work done by both in 1 minutes = a/x + a/y = a(1/x+1/y) = a(x+y)/xy
Thus, if a is the total work , then they do (x+y)/xy of a work in one minute.
Thus, (x+y)/xy portion of leaves do they rake in one minute if they work together.
