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SVETLANKA909090 [29]
3 years ago
13

Are you store sells a 28 oz. bottle of shampoo for $1.96. It also sells a 22oz. Bottle of shampoo for $1.32. Which bottle is the

better deal?
Mathematics
1 answer:
kakasveta [241]3 years ago
7 0

Answer:

28 oz. bottle of shampoo is the better priced one

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Reduce −2 + b2 by 7 + b2.
il63 [147K]
To simplify (-2+b^2)-(7+b^2), first distribute the -1 to both terms in the second parenthesis. 
-2+b^2-7-b^2
Combine like terms.
-9 (1-1=0, so the b^2 is canceled out.)
(-2+b^2)-(7+b^2)=-9
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Simplify the following expression.<br><br> 6 - (-19)
NISA [10]

Answer:

The answer is 25 but I'm not sure you can simplify a whole number

3 0
3 years ago
Could someone please help me with this? Solution set of lx^2+mx+n=0 is...?
IgorLugansk [536]

Answer:

Simplifying

lx2 + mx + n = 0

Solving

lx2 + mx + n = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1mx' to each side of the equation.

lx2 + mx + -1mx + n = 0 + -1mx

Combine like terms: mx + -1mx = 0

lx2 + 0 + n = 0 + -1mx

lx2 + n = 0 + -1mx

Remove the zero:

lx2 + n = -1mx

Add '-1n' to each side of the equation.

lx2 + n + -1n = -1mx + -1n

Combine like terms: n + -1n = 0

lx2 + 0 = -1mx + -1n

lx2 = -1mx + -1n

Divide each side by 'x2'.

l = -1mx-1 + -1nx-2

Simplifying

l = -1mx-1 + -1nx-2

Step-by-step explanation:

Hope this helped you!

6 0
3 years ago
Find the greatest common factor of 15x 2 y 3 and -20x 3 yz.
vekshin1
Multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get 
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3 years ago
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Which expression is equivalent to the following complex fraction? StartFraction 1 Over x EndFraction minus StartFraction 1 Over
Darina [25.2K]

Answer:

\frac{y-x}{x+y}

Step-by-step explanation:

We are given that fraction

\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}

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\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}

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Substitute the values  then, we get

\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}

We know that

\frac{\frac{a}{b}}{\frac{x}{y}}=\frac{a}{b}\times \frac{y}{x}

Using the property then, we get

\frac{y-x}{xy}\times \frac{xy}{x+y}

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This is required expression which is equivalent to given expression.

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3 years ago
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