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marissa [1.9K]
3 years ago
15

e vertices of a rectangle are R(-5,-5), S(-6,-5),T(-1,1),U(-5,1) a translation maps R to the point (2,-9)

Mathematics
1 answer:
Tema [17]3 years ago
7 0

Answer:

The rule of translation : (x,y)\rightarrow (x+7,y-4)

The vertices of image is R'(2,-9), S'(1,-9), T'(6,-3) and U'(2,-3).

Step-by-step explanation:

The vertices of a rectangle are R(-5,-5), S(-6,-5), T(-1,1), U(-5,1).

It is given that a translation maps R to the point (2,-9).

Difference between x-coordinates:

-5-2=-7

Difference between y-coordinates:

-5-(-9)=-5+9=4

The x-coordinate increased by 7 and y-coordinate decreased by 4. It means the figure shifts 7 units right and 4 units down.

The rule of translation is

(x,y)\rightarrow (x+7,y-4)

The vertices of image are

R(-5,-5)\rightarrow R'(-5+7,-5-4)=R'(2,-9)

S(-6,-5)\rightarrow S'(-6+7,-5-4)=S'(1,-9)

T(-1,1)\rightarrow T'(-1+7,1-4)=T'(6,-3)

U(-5,1)\rightarrow U'(-5+7,1-4)=U'(2,-3)

Therefore, the vertices of image are R'(2,-9), S'(1,-9), T'(6,-3) and U'(2,-3).

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9x+3y-4z=37<br>4x+3y +7z =16<br>x-5y +8z=-31​
Evgen [1.6K]

Answer:

x = 2 , y = 5 , z = -1

Step-by-step explanation:

Solve the following system:

{9 x + 3 y - 4 z = 37 | (equation 1)

4 x + 3 y + 7 z = 16 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 4/9 × (equation 1) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+(5 y)/3 + (79 z)/9 = -4/9 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Multiply equation 2 by 9:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 1/9 × (equation 1) from equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - (16 y)/3 + (76 z)/9 = -316/9 | (equation 3)

Multiply equation 3 by 9/4:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - 12 y + 19 z = -79 | (equation 3)

Add 4/5 × (equation 2) to equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+(411 z)/5 = -411/5 | (equation 3)

Multiply equation 3 by 5/411:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 79 × (equation 3) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y+0 z = 75 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 2 by 15:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 3 × (equation 2) from equation 1:

{9 x + 0 y - 4 z = 22 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Add 4 × (equation 3) to equation 1:

{9 x+0 y+0 z = 18 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 1 by 9:

{x+0 y+0 z = 2 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Collect results:

Answer:  {x = 2 , y = 5 , z = -1

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