Elena and Jorge have similar problems and find the same answer. Each determines that the solution to e problem is 24.

La suma de tres números enteros consecutivos es 156 halla los números

mars1129 [50]

Esta es la respuesta 51+52+53= 156

3 0

3 years ago

Can i please get help with this question?

Feliz [49]

The first letter because 1•5 = 5. 2•5 equals ten etc

4 0

3 years ago

Is of 12 equal to 9?<br>no

Vesnalui [34]

Answer:

12=9

Obviously

.................

4 0

3 years ago

X-23 / x^2 -x- 20 - 2/5-x

alexira [117]

By simplifying $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$ . This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

The Simplifying Algorithm is a wonderful way to simplify complex mathematics problems. It can be used to solve equations, convert fractions to decimals, and perform many other math operations. In this problem, the Simplifying Algorithm will help you reduce $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$

Since two opposites add up to 0, remove them from the expression.

$- \frac{{23}}{{{x^2}}} - \frac{{102}}{5} - x$

Write all numerators above the least common denominator 5x2

$- \frac{{115 + 102{x^2} + 5{x^3}}}{{5{x^2}}}$

Use the commutative property to reorder the terms so that constants on the left

$\frac{{ - 5{x^3} - 115 - 102{x^2}}}{{5{x^2}}}$

Rearrange the terms

$\frac{{ - 5{x^3} - 102{x^2} - 115}}{{5{x^2}}}$

By reording the terms

$- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$

Hence, by simplifying this equation, divide both numerator and denominator. This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

To learn more about simplifyication visit:

brainly.com/question/1542396

#SPJ1

7 0

1 year ago

During the national day celebrations.Asha decorates her balcony with serial lights of red,green and white colours.The red light

expeople1 [14]

If all three coloured lights blink together at 8:49 pm, they will blink together at 8:50 pm

<u>Solution:</u>

Given that the red light blinks at intervals of 4 seconds, the green at 5 seconds and the white at 6 seconds.

If all three colored lights blink together at 8:49 pm,

We have to find when will they blink together again?

First let us know, at what intervals they all together blink.

For that we have to find the lcm of 4, 5, 6.

L.C.M (4, 5, 6) = 2 x L.C.M(2, 5, 3)

As 2,3,5 are primes, we can’t take common further, so multiply all

= 2 x 2 x 5 x 3

= 4 x 15 = 60

So, after every 60 seconds = 1 minute they will blink.

Then, after 8 : 49 pm, they will blink at 8 : 49 + 1 = 8 : 50 pm.

Hence, they all blink at 8 : 50 pm.

6 0

3 years ago