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Maru [420]
3 years ago
11

Zach is deciding how he is going to spend his day. He can go to the library or to the mall, he can walk or bike, and he can go a

lone or with a friend. What are all the possible ways Zach can spend his day? Select from the drop-down menus to correctly complete the sample set list. library, walk, alone library, , with a friend library, bike, alone library, bike, with a friend mall, walk, alone mall, walk, with a friend mall, bike, alone mall, , with a friend
Mathematics
2 answers:
antoniya [11.8K]3 years ago
7 0
(1) First answer on the box is "Walk"
(2) Second answer on the box is "bike"

Hope this helps you!

Hoochie [10]3 years ago
4 0
(1.Walk) (2.Bike) I hope this helps!
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Peter takes 7 minutes and 30 seconds to run 1 mile. How many miles can he run in 15 minutes?
goblinko [34]
2 miles in 15 mins.. i think.
5 0
3 years ago
Read 2 more answers
Write the following in order from smallest to largest: 3\12, 0.146, 5\7, 0.279
Brrunno [24]

Answer:

3/12 0.146 0.279 5/7

Step-by-step explanation:

3/12 = 0.25

5/7 = 0.71428571428

6 0
3 years ago
What is the EQUATION of the line PERPENDICULAR to y=-2x+5 and passing through the point (0,2)?
KonstantinChe [14]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The required equation is ~

\boxed{ \sf{y =  \frac{x}{2} + 2 }}

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's find the slope of given line ~

  • y =  - 2x + 5

comparing it with general slope - intercept form of line (y = mx + c) we get, m = -2 (that is slope of the line)

let the slope of the required line be n

And, now since the required line Is perpendicular to the given line. the product of their slopes is -1

that is ~

  • - 2 \times n =  - 1

  • n = \dfrac{ - 1}{ - 2}

  • n =  \dfrac{1}{2}

slope of required line is ~ 1/2

now, let's use the point - slope form of line to find the equation of required (perpendicular) line (using point (0 , 2) ~

that is ~

  • y - y_1 = m(x - x_ 1)

here, m = slope ~

  • y - 2 =  \dfrac{1}{2} (x - 0)

  • y - 2 =  \dfrac{x}{2}

  • y =  \dfrac{x}{2}  + 2

I hope it helps ~

4 0
2 years ago
If : f(x)=x^2, g(x)=x-1. Find (f×g)(x).<br>​
kramer

Answer:

  • \boxed{ f\cdot{g}(x) = x {}^{3}  - x {}^{2}}

Step by step explanation:

Given that,

f(x) =  {x}^{2}

g(x) = x - 1

Solution:

Solving for (f•g)(x):

= f(x) \cdot g(x)

Now substitute the given values.

= x {}^{2}  \cdot(x - 1)

= x {}^{2} (x - 1)

Apply distributive property:

= (x ^{2}  \cdot x) - x {}^{2}  \cdot 1

  • \boxed{ f\cdot{g}(x) =  x {}^{3}  - x {}^{2}}

Hence,f•g(x) will be x {}^{3}  - x {}^{2}.

8 0
2 years ago
What is the correct answer?
Svetlanka [38]

Answer:

Terms must have the same variable (letter) and the same exponent (little number)

(7x² +3y+ 5) +(9x²+11y- 2)

Opening bracket

7x²+3y+5+9x²+11y-2

keeping like terms together

7x²+9x²+3y+11y+5-2

Since terms having same variable and exponent can be subtracted, added,divided and multiplied

So

Solving like terms we get

<u>16x²+14y+3</u> which is a correct answer.

4 0
2 years ago
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