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Colt1911 [192]
2 years ago
8

Cual es la ecuación de la recta que pasa por el punto (2;-1/2) y tiene de pendiente m=-2/3

Mathematics
1 answer:
timama [110]2 years ago
4 0

Answer:

y = (-2/3)x + 5/6

Step-by-step explanation:

The general structure of a line in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m". To find the value of "b", you can plug the slope and the values from the point (2, -1/2) into the general equation.

m = -2/3

Point (2, -1/2):

x = 2 and y = -1/2

y = mx + b                                  <----- Slope-intercept form

y = (-2/3)x + b                            <----- Insert -2/3 in "m"

-1/2 = (-2/3)(2) + b                      <----- Insert "x" and "y" values from point

-1/2 = -4/3 + b                            <----- Multiply -2/3 and 2

-3/6 = -8/6 + b                           <----- Give the fractions common denominators

5/6 = b                                      <----- Add 8/6 to both sides

Thus, the equation of the line is:

y = (-2/3)x + 5/6

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