WORTH 20 POINTS PLEASE HELP ME

The reason why is because each bag is separate from one another, so one event doesn't affect the other. If we know the result of what we pulled out of one bag, it doesn't change the probability of the other event.

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Problem 2

Answer: Dependent

Assuming you do not put the first card back, then the probability of picking a King on the second draw will be different than if you picked a King on the first draw. With all 52 cards in the deck, the probability of getting a king is 4/52 = 1/13. It changes to 4/51 after we picked out an ace for the first card (and didn't put that first card back).

6 0

3 years ago

I WILL MARK YOU BRAINLYEST if you answer all of my problems !!!!!!!!!!!

Romashka [77]

First, let's convert each line to slope-intercept form to better see the slopes.

Isolate the y variable for each equation.

2x + 6y = -12

Subtract 2x from both sides.

6y = -12 - 2x

Divide both sides by 6.

y = -2 - 1/3x

Rearrange.

y = -1/3x - 2

Line b:

2y = 3x - 10

Divide both sides by 2.

y = 1.5x - 5

Line c:

3x - 2y = -4

Add 2y to both sides.

3x = -4 + 2y

Add 4 to both sides.

2y = 3x + 4

Divide both sides by 2.

y = 1.5x + 2

Now, let's compare our new equations:

Line a: y = -1/3x - 2

Line b: y = 1.5x - 5

Line c: y = 1.5x + 2

Now, the rule for parallel and perpendicular lines is as follows:

For two lines to be parallel, they must have equal slopes.

For two lines to be perpendicular, one must have the negative reciprocal of the other.

In this case, line b and c are parallel, and they have the same slope, but different y-intercepts.

However, none of the lines are perpendicular, as -1/3x is not the negative reciprocal of 1.5x, or 3/2x.

<h3><u>B and C are parallel, no perpendicular lines.</u></h3>

8 0

3 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

3 years ago