Answer:
The cost of 16 oz of granola should be $16.16
Step-by-step explanation:
Given that,
The cost of 3 oz of granola is $3.03
We need to find the cost of 16 oz of granola..
As 3 oz = $3.03
1 oz = (3.03/3) = $1.01
The cost of 16 oz will be :
16 oz = 16×1.01
= $16.16
Hence, the cost of 16 oz of granola should be $16.16.
Answer:
SSS
Both these triangles are congruent to each other by SSS congruency
Hope it helps
Answer:
£13496.80
Step-by-step explanation:
We can ignore the £ sign for now, that is just units.
If we decrease a number by 4.5%, we will have to find
% of 14132.77.
We can easily do this by setting up a proportion.

Multiply 14132.77 by 95.5:

Divide by 100:

Rounding this to two decimal places, it simplifies to 13496.80.
Hope this helped!
Answer:
5400 cubes can be fit into the prism.
Step-by-step explanation:
We are given the dimensions of prism as:
5 units by 5 units by 8 units i.e. 5 units×5 units×8 units.
Hence, the volume of the prism is given by:
Volume of prism=5×5×8=200 cubic units
Also the edge length of cube is given by= 1/3 unit.
Hence volume of 1 cube=
Hence volume of 1 cube= (1/27) cubic units.
Let 'n' cubes can be fitted into the prism.
Hence we have the relation as:
Volume of prism=n×Volume of 1 cube.
200=n×(1/27)
n=200×27
n=5400
Hence 5400 cubes can be fitted into the prism.
<h2><u><em>
NUMBER THREE</em></u></h2>
Answer:
The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean
and standard deviation 
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean
and standard deviation 
In this question:

Then

By the Central Limit Theorem:
The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean
and standard deviation 