Answer:
Step-by-step explanation:
Given:
∠DCE ≅ ∠DEC
∠B ≅ ∠F
DF ≅ BD
To prove:
ΔABC ≅ ΔGFE
Solution:
Statements Reasons
1). ∠DCE ≅ ∠DEC 1). Given
2). ∠ACB ≅ ∠GEF 2). Vertically opposite angles to the
congruent angles.
3). ∠B ≅ ∠F 3). Given
4). DB ≅ DF 4). Given
5). DC + CB ≅ DE + EF 5). Segment addition postulate
6). DC ≅ DE 6). Property of isosceles triangle
7). CB ≅ EF 7). Transitive property
8). ΔABC ≅ ΔGFE 8). ASA property of congruence
Answer:
This would be a regular polygon.
Step-by-step explanation:
A regular polygon has congruent sides and interior angles.
An irregular polygon does not have congruent sides and all interior angles.
A convex polygon does not have a interior angle greater than 180°.
Lastly, a concave polygon has only one interior angle greater than 180°.
Using the process of elimination, it would not be a convex or concave polygon. Now we have either a regular or irregular polygon. This polygon can not be a irregular polygon because all the sides are congruent. This means that this polygon is a regular polygon!
90 - 40 = 50
Complementary angles add up to 90 degrees.
If one angle is 40 degrees less than the other, you just put it into an equation where 40 is subtracted from 90.
The answer would then be 50 degrees.
