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Lera25 [3.4K]
3 years ago
6

The probability that you roll a two on a six-sided die is 16. If you roll the die 60 times, how many twos can you expect to roll

?
Mathematics
2 answers:
disa [49]3 years ago
5 0
You’re answer is 960.

If you roll the die once the probability it 16. But if you were to roll it 60 times the math you would have to do would be: 60*16=960. Simpler than you may think.

Hope this helps!!
Stels [109]3 years ago
3 0
Answer: 960

Explanation:

If you roll one time the probability is 16
Then if you roll 60 times the probability is:

16 x 60 = 960

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The we are readers book club allows members to buy book for $8.75 per book.The print is dead book club cost $20 to join and allo
Likurg_2 [28]
$8.75x = $6.25x + $20

$8.75x -$6.25x = $20

$2.50x = $20

So when x = 8, $8.75 x 8 books= $70 and $6.25 x 8 books = $50 + $20 club fee = $70

7 0
2 years ago
At the grocery store, Alan can buy 4 cans of soup for $2. At the warehouse store the same soup costs $5.76 for 12 cans, which pl
Damm [24]

Answer:

The warehouse has a better price

Step-by-step explanation:

It has a better price because each can at the grocery store is $0.50, the warehouse sells each can for $0.48. The difference is $0.02.

6 0
3 years ago
5+5 you get 52 points for answering this question
Aleks [24]

Answer:

10

Step-by-step explanation:

We're looking for 5 + 5:

x = 5 + 5

Since 5 + 5 = 10:

x = 5 + 5

x = 10

Answer: 10

4 0
3 years ago
There are 60 animal exhibits at the local zoo. What percent of the zoo's exhibits does each animal class represent?​
snow_lady [41]

Answer:

30+15+12+3=  60

for mammal 30/60=0.50%

reptile 15/60=0.25%

fish  12/60= 0.20%

bird 3/60=0-05%

i hope that helps

8 0
3 years ago
It cost 5 dollars for a child ticket and 8 dollars for a adult ticket. Total tickets sold were 110 bringing in 820 dollars? How
omeli [17]

Number of child tickets bought is 20

<h3><u>Solution:</u></h3>

Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket

cost of each child ticket = 5 dollars

cost of each adult ticket = 8 dollars

Let "c" be the number of child tickets bought

Let "a" be the number of adult tickets bought

Total tickets sold were 110 bringing in 820 dollars

<em>Number of child tickets bought + number of adult tickets bought = 110</em>

c + a = 110 ----- eqn 1

<em><u>Also we can frame a equation as:</u></em>

Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

c \times 5 + a \times 8 = 820

5c + 8a = 820 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

From eqn 1,

a = 110 - c  ------ eqn 3

Substitute eqn 3 in eqn 2

5c + 8(110 - c) = 820

5c + 880 - 8c = 820

-3c = - 60

c = 20

Therefore from eqn 3,

a = 110 - 20 = 90

a = 90

Therefore number of child tickets bought is 20

8 0
3 years ago
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