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-BARSIC- [3]
3 years ago
5

D’Quan’s grandmother made a quilt for his bed. The quilt is

Mathematics
2 answers:
damaskus [11]3 years ago
7 0
One Square Meter= 10.764 Square Feet.
The total area of the quilt in meters is 4.465m^{2}
As you're looking for square feet, you've then got to multiply this by 10.764
4.465*10.764= 48.06086 square feet.
Rounded, this is 48.06 square feet.
Hope this helps :) 
n200080 [17]3 years ago
4 0
2.44 * 1.83 = 4.4652 m^2 ;
4.4652 * 10.7639 = 48.0629 square feet ;
Rounded, 48.06 square feet.
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A car is traveling along a test track in the desert at a constant rate of 85 feet per second The test track has a length of 10,0
jeyben [28]

Answer:

foot marker 320 at t=0

Step-by-step explanation:

8 sec x 85 ft/s =680 ft

1,000ft - 680 ft = 320 ft

4 0
3 years ago
PLSSSS HELPPP I WILLL GIVEEE BRAINLIESTTTT!!!!!!!!!!!!!!!!!
agasfer [191]

Answer: use a slope calculator

-1/6

Step-by-step explanation:

4 0
3 years ago
Find the indicated conditional probability
andrezito [222]

Given:

The two way table.

To find:

The conditional probability of P(Drive to school | Senior).

Solution:

The conditional probability is defined as:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Using this formula, we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{P(\text{Drive to school and senior})}{P(\text{Senior})}                      ...(i)

From the given two way table, we get

Drive to school and senior = 25

Senior = 25+5+5

           = 35

Total = 2+25+3+13+20+2+25+5+5

         = 100

Now,

P(\text{Drive to school and senior})=\dfrac{25}{100}

P(\text{Senior})=\dfrac{35}{100}

Substituting these values in (i), we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{\dfrac{25}{100}}{\dfrac{35}{100}}

P(\text{Drive to school }|\text{ Senior})=\dfrac{25}{35}

P(\text{Drive to school }|\text{ Senior})=0.7142857

P(\text{Drive to school }|\text{ Senior})\approx 0.71

Therefore, the required conditional probability is 0.71.

5 0
3 years ago
Read 2 more answers
Given h(x) = x^ - 2, what is the value of h(-3) ?<br><br> ^ = is exponent 2
ella [17]

Answer:

  • 1/9

Step-by-step explanation:

<u>Given</u>

  • h(x) = x^ - 2
  • h(-3) = ?

<u>Substitute x with -3</u>

  • h(-3) = (-3)^-2 = 3^-2 = 9^-1 = 1/9
3 0
3 years ago
Read 2 more answers
the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
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