Answer:
y
=
4
(
1
2
)
x
Explanation:
An exponential function is in the general form
y
=
a
(
b
)
x
We know the points
(
−
1
,
8
)
and
(
1
,
2
)
, so the following are true:
8
=
a
(
b
−
1
)
=
a
b
2
=
a
(
b
1
)
=
a
b
Multiply both sides of the first equation by
b
to find that
8
b
=
a
Plug this into the second equation and solve for
b
:
2
=
(
8
b
)
b
2
=
8
b
2
b
2
=
1
4
b
=
±
1
2
Two equations seem to be possible here. Plug both values of
b
into the either equation to find
a
. I'll use the second equation for simpler algebra.
If
b
=
1
2
:
2
=
a
(
1
2
)
a
=
4
Giving us the equation:
y
=
4
(
1
2
)
x
If
b
=
−
1
2
:
2
=
a
(
−
1
2
)
a
=
−
4
Giving us the equation:
y
=
−
4
(
−
1
2
)
x
However! In an exponential function,
b
>
0
, otherwise many issues arise when trying to graph the function.
The only valid function is
y
=
4
(
1
2
)
x
4, 7 and 9 are mutually coprime, so you can use the Chinese remainder theorem.
Start with

Taken mod 4, the last two terms vanish and we're left with

We have
, so we can multiply the first term by 3 to guarantee that we end up with 1 mod 4.

Taken mod 7, the first and last terms vanish and we're left with

which is what we want, so no adjustments needed here.

Taken mod 9, the first two terms vanish and we're left with

so we don't need to make any adjustments here, and we end up with
.
By the Chinese remainder theorem, we find that any
such that

is a solution to this system, i.e.
for any integer
, the smallest and positive of which is 149.
Answer:
perimeter = 82 inches
Step-by-step explanation:
To find the perimeter, add all of the side lengths together
I think the answer is 75.6 because i divided 36 cards by 5 folders and i got 1.2. And then i divided 372 extra cards by 5 folders am got 74.4. I add the two total and have 75.6
5/36 = 1.2 5/372 = 74.4
1.2+74.4= 75.6 srry if I'm wrong
Answer:

Step-by-step explanation:
Given
The attached rhombus
Required
The area
First, calculate the length of half the vertical diagonal (x).
Length x is represented as the adjacent to 60 degrees
So, we have:

Solve for x


So:


At this point, we have established that the rhombus is made up 4 triangles of the following dimensions


So, the area of the rhombus is 4 times the area of 1 triangle



