Given :
Center of sphere , C( 1 , -1 , 6 ) .
To Find :
Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .
Solution :
a)
Distance of the point from xy-plane is :
d = 6 units .
So , equation of circle with center C and radius 6 units is :
b)
Distance of point from yz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :
c)
Distance of point from xz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :
Hence , this is the required solution .
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Answer:
x = 14
Step-by-step explanation:
Step 1: First, Simplify the fraction.
Step 2: Next, Multiply both sides by 7.
4x = 8 × 7
Step 3: Simplify 8 × 7 to 56.
4x = 56
Step 4: Then, Divide both sides by 4.
Step 5: Lastly, Simplify the fraction and you're done!
x = 14
There’s a 2/6 chance that the science project would be first
Answer:
Step-by-step explanation:
we know that
In a join variation, If j varies jointly with respect to g and v, the equation will be of the form 
where k is a constant
step 1
Find the value of k
we have
j=2,g=4,v=3
substitute and solve for k
The equation is equal to
step 2
Find the value of j when g=8,v=9
substitute the values in the equation and solve for j
