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3 years ago

8

What is the distance between –6 and –2 on a number line?

2 answers:

IRISSAK [1]3 years ago

4 0

For this case we have to observe the numerical line of the attached figure, we find that from -2 to -6 there are 4 units. Remember that distance should always be a positive value. So:

$| -4 | = 4$

Answer:

4 units

See attached image

kogti [31]3 years ago

3 0

Answer:

lets refer to the # on the #line as spaces. -6 is 6 spaces left of 0. -2 is 2 spaces left of 0

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Multiply and verify the result by taking x=1 y=2 z=3 (2x-2y) to the power 2

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Answer:

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Step-by-step explanation:

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3 years ago

(3squared)squared x(10cubed)squared

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3 years ago

Read 2 more answers

Find the product of 3 and the linear equation, and solve for both equations for y.

krok68 [10]

Answer:

Part 1) The product of 3 and 2y-4x=8 is $6y-12x=24$

Part 2) The original equation in slope intercept form is $y=2x+4$

Part 3) The new equation in slope intercept form is $y=2x+4$

Step-by-step explanation:

we have

$2y-4x=8$

step 1

Find out the product of 3 and 2y-4x=8

Multiply both sides by 3

$3(2y-4x)=3(8)$

Apply distributive property both sides

$6y-12x=24$

step 2

Find out the original equation in slope intercept form

The equation of the line in slope intercept form is

$y=mx+b$

we have

$2y-4x=8$

Solve for y

That means ----> Isolate the variable y

Adds 4x both sides

$2y=4x+8$

Divide by 2 both sides

$y=(4x+8)/2$

Simplify

$y=2x+4$

step 3

Find out the new equation in slope intercept form

The equation of the line in slope intercept form is

$y=mx+b$

we have

$6y-12x=24$

Solve for y

That means ----> Isolate the variable y

Adds 12x both sides

$6y=12x+24$

Divide by 6 both sides

$y=(12x+24)/6$

Simplify

$y=2x+4$

8 0

3 years ago

50 POINTS!!!!!<br> Consider the picture below. Find the measure of ∠A

True [87]

Answer:

103°

Step-by-step explanation:

∠CEA and ∠DEB are vertically opposite angles same as ∠CED and ∠AEB.

Vertically opposite angles are angles that form when two lines intersect

From the figure given, lines CB and AD intersect to form vertically opposite angles mentioned above. Vertically opposite angles are equal, meaning

∠CEA=∠DEB and ∠CED=∠AEB

Replacing ∠CED=∠AEB, we get

(14x+7)°=(12x+17)°

Solve for x

(14x-12x)=17-7

2x=10

x=10÷2=5

value for x in ∠CED=∠AEB, we get (14×5)+7=77°

To calculate ∠CEA and ∠DEB

Let ∠CEA=∠DEB=y

∠DEA=180°since its a straight line therefor

(14x+7)°+y=180°

77+y=180

y=∠CEA=∠DEB=103°

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3 years ago

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Alexxandr [17]

Answer:

its a three out of seven then it stays the same

Step-by-step explanation:

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3 years ago