For this case we have to observe the numerical line of the attached figure, we find that from -2 to -6 there are 4 units. Remember that distance should always be a positive value. So:
Answer:
4 units
See attached image
lets refer to the # on the #line as spaces. -6 is 6 spaces left of 0. -2 is 2 spaces left of 0
3y-7
Step-by-step explanation:
-4y + 7y - 10 + 3
Combine like terms
3y -7
(m-(1/3))(m^2+(1/3)m+(1/9)
Just use the difference of cubes
Umm I'm not entirely sure but I think its the last one
Answer:2
IM FAST RIGHT???