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brilliants [131]

3 years ago

5

On Friday, 80 children and 48 adults went to a movie. What was the ratio of children to adults? A 5 to 3 B 10 to 4 C 6 to 3 D 2

to 1

2 answers:

Setler79 [48]3 years ago

7 0

A . Because one you make the ratio 80:48 you simplify (divide until you can divide anymore ).

Sav [38]3 years ago

6 0

A 5to3 hope this is what you needed

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Find a formula for the sum of the first n even integers : 2 + 4 + 6 + ... + 2n.

Sedbober [7]

Let S be the sum,

S = 2 + 4 + 6 + ... + 2 (n - 2) + 2 (n - 1) + 2n

Reverse the order of terms:

S = 2n + 2 (n - 1) + 2 (n - 2) + ... + 6 + 4 + 2

Add up terms in the same positions, so that twice the sum is

2S = (2n + 2) + (2n + 2) + (2n + 2) + ... + (2n + 2)

or

2S = n (2n + 2)

Divide both sides by 2 to solve for S :

S = n (n + 1)

7 0

2 years ago

Jo bought a used car for $6000 and paid 15% deposit. How much does he still have to pay?

AlexFokin [52]

15%=0.15

6000×0.15=900

He paid $900 (15% of $6000; 6000×0.15=900)

$6000-$900= $5100

and he still have to pay $5100

4 0

3 years ago

Read 2 more answers

Find the surface area and volume of a cube with sides of 5.5 cm each.

djyliett [7]

Answer:

Area: 181.5

Volume: 166.4

Step-by-step explanation:

Hope this helps.

6 0

3 years ago

Middletown sponsors a two day conference for selected middle school students to study government. Suppose 20 student delegates w

grandymaker [24]

Answer:

North Middle School = 10 students
Central Middle School = 6 students
South Middle School = 4 students

Step-by-step explanation:

First calculate the total number of students in all the schools:

= 618 + 378 + 204

= 1,200 students

Use this number to calculate the proportion of the total population that a school so that this can then be used to determine the proportion of the 20 delegates they should sent.

North Middle school:

= 618/1,200 * 20

= 10 students

Central Middle School:

= 378 / 1,200 * 20

= 6 students

South Middle School:

= 204/1,200 * 20

= 4 students

5 0

3 years ago

diamong [38]

Answer:

Cos A=5/13

we have

Cos² A= $1-Sin ²A$

25/169=1-Sin²A

sin²A=1-25/169

sin²A=144/169

Sin A= $\sqrt{144/169}=12/13$

again

Tan B=4/3

P/b=4/3

p=4

b=3

h= $\sqrt{3²+4²}=5$

Now

Sin B=p/h=4/5

in IV quadrant sin angle is negative so

Sin B=-4/5

CosB=b/h=3/5

Now

<u>S</u><u>i</u><u>n</u><u>(</u><u>A</u><u>+</u><u>B</u><u>)</u><u>:</u><u>s</u><u>i</u><u>n</u><u>A</u><u>c</u><u>o</u><u>s</u><u>B</u><u>+</u><u>C</u><u>o</u><u>s</u><u>A</u><u>s</u><u>i</u><u>n</u><u>B</u>

<u>n</u><u>o</u><u>w</u><u> </u>

<u>substitute</u><u> </u><u>value</u>

<u>Sin(A+B):</u>12/13*3/5+5/13*(-4/5)=36/65-4/13

<u>=</u><u>1</u><u>6</u><u>/</u><u>6</u><u>5</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u>

6 0

3 years ago