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marysya [2.9K]
3 years ago
7

As you move from ice to water to steam, which statement is true? A) Temperature, density, and compressibility all increase. Elim

inate B) Temperature, kinetic energy, and compressibility all increase. C) Temperature and compressibility increase as molecular motion decreases. D) Temperature and kinetic energy increases while compressibility decreases.
Physics
1 answer:
aleksley [76]3 years ago
3 0

Answer:

B) Temperature, kinetic energy, and compressibility all increase.

Explanation:

The temperature increases, since the boiling point of water is greater than its melting point. The average kinetic energy of the molecules is proportional to their temperature, therefore, it also increases. Finally, solids are very difficult to compress, since their molecules are very close, while gases have very separate molecules, therefore, they are highly compressible.

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Physical properties used to measure stars include
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a high speed train travels with an average speed of 250 km/h. the train travels for 2 hrs. how far does the train travel
steposvetlana [31]

Answer:

<h3>The answer is 500 km </h3>

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

<h3>distance = average velocity × time</h3>

From the question

average speed = 250 km/h

time = 2 hrs

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distance = 250 × 2

We have the final answer as

<h3>500 km</h3>

Hope this helps you

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4 years ago
The velocity of a particle traveling in a straight line is given by v = (6t - 3t²) m/s, where t is in seconds. If s = 0 when t =
qaws [65]

Answer

given,

v = (6 t - 3 t²) m/s

we know,

v = \dfrac{dx}{dt}

a = \dfrac{dv}{dt}

position of the particle

dx = v dt

integrating both side

\int dx = (6t - 3 t^2)\int dt

 x = 3 t² - t³

Position of the particle at t= 3 s

 x = 3  x 3² - 3³

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now, particle’s deceleration

a = \dfrac{dv}{dt}

a = \dfrac{d}{dt}(6t - 3 t^2)

  a = 6 - 6 t

at t= 3 s

    a = 6 - 6 x 3

    a = -12 m/s²

distance traveled by the particle

  x = 3 t² - t³

at t = 0 x = 0

   t = 1 s   , x = 3 (1)² - 1³ = 2 m

   t = 2 s  ,  x = 3(2)² - 2³ = 4 m

   t = 3 s ,   x =  0 m

total distance traveled by the particle

D = distance in 0-1 s + distance in 1 -2 s + distance in 2 -3 s

D = 2 + 4 + 2 = 8 m

average speed of the particle

v_{avg} = \dfrac{distance}{time}

v_{avg} = \dfrac{8}{3}

v_{avg} =2.67\ m/s

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