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kodGreya [7K]
3 years ago
11

Why does a person while firing a bullethold the gun tightly to his shoulders?

Physics
1 answer:
Taya2010 [7]3 years ago
6 0

Answer:

here's your ans......

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Jack and Jill are maneuvering a 3300 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is
Paraphin [41]

Answer:

The workdone by Jack is  W_{jack} = -1050J

The workdone by Jill is  W_{Jill} = 0J

The final velocity is  v = 1.36 m/s

Explanation:

From the question we are given that

          The mass of the boat is m_b = 3300kg

          The initial position of the boat is   P_i  = (2 \r  i  + 0 \r j + 3\r k)m

           The Final position of the boat is  P_f = (4\r i + 0 \r j + 2\r k )\ m

           The Force exerted by Jack \r F = (-420\r i + 0 \r j + 210\r k) \ N

             The Force exerted by Jill  \r F_{Jill} =(180 \r i + 0\r j + 360\r k)

Now to obtain the displacement made we are to subtract the final position from the initial position

                                 \r P = P_f - P_i

                                    = (4\r i + 0\r j + 2 \r k) - (2\r i + 0\r j + 3\r k  )

                                     = (2\r i + 0\r j -\r k )m

Now that we have obtained the displacement we can obtain the Workdone

  which is mathematically represented as

                                                   W =\r  F * \r P

 The amount of workdone by jack would be

                                               W_{jack} =\r  F * \r P

                                                 = [(-420\r i +0\r j +210\r k)(2\r  i + 0\r j - \r k)]

                                                 = (-420) (2) + (210)(-1)

                                                = -840 - 210

                                               =-1050J

  The amount of workdone by Jill would be

                                                 W_{Jill} =\r  F * \r P

                                                        = [(180 \r i + 0\r j + 360\r k)(2\r i +0\r j -\r k)]

                                                       = (180 )(2) +(360)(-1)

                                                       =0J

According to work energy theorem the Workdone is equal to the kinetic energy of the boat

              W = K.E = \frac{1}{2} m *[v^2 - (1.1)^2]

             -1050  = 0.5*3300 [*v^2- (1.1)^2]

            -1050 = 1650 [v^2 -1.21]

               0.6363 = v^2 -1.21

                   v^2 = 0.6363+1.21

                    v^2 =1.846

                    v = 1.36\ m/s

                   

6 0
4 years ago
Newton’s heliocentric view of the universe meant that the sun was the center of the universe. True False
Anuta_ua [19.1K]
The answer to this question is true.
7 0
4 years ago
Read 2 more answers
GIZMO
CaHeK987 [17]
It is A or D but I believe A
5 0
3 years ago
1.15) What distance will 650 joules of work move a box weighing 50 newtons?​
son4ous [18]

Answer:

The answer is 13 however make sure if they ask for a certain measurement like meter answer it by saying 13 meters.

Explanation:

This basically turns into basic algebra if you know the formula for work. The formula for work is W=F*d  

Here are the variables that you know 650J=50N*d so you need d.

All you do is divide 650J by 50N and you get a total of 13 (meters since I don't know what they want you to put it in).

6 0
3 years ago
After watching a video about submarines, Jamil wants to learn more about the ocean. which question could be answered through sci
SOVA2 [1]
<span>Submarines are equipped with water tanks called ballast tanks that fill up to submerge the vessel. Emptying the tanks and filling them with air causes the submarine to surface.</span>
5 0
3 years ago
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