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marishachu [46]
2 years ago
10

a high speed train travels with an average speed of 250 km/h. the train travels for 2 hrs. how far does the train travel

Physics
2 answers:
Afina-wow [57]2 years ago
7 0

Answer:

The answer would be 454 miles.

Explanation:

You multiply the average speed by time travelled. Hope this helps!

steposvetlana [31]2 years ago
5 0

Answer:

<h3>The answer is 500 km </h3>

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

<h3>distance = average velocity × time</h3>

From the question

average speed = 250 km/h

time = 2 hrs

We have

distance = 250 × 2

We have the final answer as

<h3>500 km</h3>

Hope this helps you

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I really need help with this to be able to pass this last semester this is about (Circular Motion ) on physics
ankoles [38]
Question 1
To find centripetal acceleration, use the formula : centripetal acceleration = v^2/r
so answer would be (3.71)^2/42.85=0.32 (2d.p.)
Question 2
Force =ma
a= (9.98)^2/31.77=3.1350
Force= 3.1350 * 56.63 = 177.54 (2 d.p.)
4 0
3 years ago
Read 2 more answers
A wire of length 6cm makes an angle of 20° with a 3 mT
Crazy boy [7]

Answer:

Approximately 7.3 \times 10^{-3}\; \rm A (approximately 7.3\; \rm mA) assuming that the magnetic field and the wire are both horizontal.

Explanation:

Let \theta denote the angle between the wire and the magnetic field.

Let B denote the magnitude of the magnetic field.

Let l denote the length of the wire.

Let I denote the current in this wire.

The magnetic force on the wire would be:

F = B \cdot l \cdot I \cdot \sin(\theta).

Because of the \sin(\theta) term, the magnetic force on the wire is maximized when the wire is perpendicular to the magnetic field (such that the angle between them is 90^\circ.)

In this question:

  • \theta = 20^\circ (or, equivalently, (\pi / 9) radians, if the calculator is in radian mode.)
  • B = 3\; \rm mT = 3 \times 10^{-3}\; \rm T.
  • l = 6\; \rm cm = 6 \times 10^{-2}\;\rm m.
  • F = 1.5\times 10^{-4}\; \rm N.

Rearrange the equation F = l \cdot I \cdot \sin(\theta) to find an expression for I, the current in this wire.

\begin{aligned} I &= \frac{F}{l \cdot \sin(\theta)} \\ &= \frac{3\times 10^{-3}\; \rm T}{6 \times 10^{-2}\; \rm m \times \sin \left(20^{\circ}\right)} \\ &\approx 7.3 \times 10^{-3}\; \rm A = 7.3 \; \rm mA\end{aligned}.

5 0
2 years ago
Two coils, held in fixed positions, have a mutual inductance of M = 0.0034 H. The current in the first coil is I(t) = I0sin(ωt),
tiny-mole [99]

Answer:

ε₂ =2.63 V

Explanation:

given,

M = 0.0034 H

I (t) = I₀ sin (ωt)

I (t) = 5.4 sin (143 t)

\dfrac{d i(t)}{dt} = \dfrac{d}{dt}(5.4 sin (143 t))

\dfrac{d i(t)}{dt} =143 \times 5.4 cos (143 t)

magnitude of the induced emf in the second coil

ε₂ =M\dfrac{di}{dt}

ε₂ =0.0034\times 143 \times 5.4 cos (143 t)

for maximum emf

cos (143 t) = 1

ε₂ =0.0034\times 143 \times 5.4

ε₂ =2.63 V

3 0
2 years ago
PLEASE HELP WILL GIVE 10 POINTS!!!!
katrin2010 [14]

The correct answer would be A

3 0
3 years ago
Read 2 more answers
V = d/t please help with my physics question!
Assoli18 [71]

Answer:

313, 0.60 s

Explanation:

wavelength

= speed/frequency

= 340/520

= 0.6538 m

Number of wavelengths

= 205/0.6538

= <u>313</u> (whole number)

Time delay

= distance/speed

= 204/340

= <u>0.60 s</u>

7 0
2 years ago
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