<span>The area in the right tail more extreme than z= 3.01 in a standard normal distribution is given by
P(z > 3.01) = 1 - P(z < 3.01) = 1 - 0.99869 = 0.00131
</span>
6 because 54 divided by 9 is 6
I hope this helps but the answer is 913 hope it helps
The z-score is given by:
z=(x-mean)/s.d
the z-score giving us P(0.95)=1.96 and -1.96
thus;
-1.96=(x-1500)/300
-588=x-1500
x=-588+1500
x=912
also:
1.96=(x-1500)/300
588=x-1500
x=588+1500
x=2,088
therefore the sample size of the student picked will be given by:
2,088-912
=1,176
