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Dmitrij [34]
2 years ago
9

A crewman on a fishing boat was injured and needs to be treated in a hospital right away. You are with a Coast Guard station nea

rest to the boat, but you are 400 miles away. The boat travels at a rate of 10 mph. It is 5:30 A.M. You have a helicopter that can hold 6600 lbs. of fuel, consumes 1200 pounds of fuel an hour, and travels 150 mph. However, you need to save a minimum of 1 hour worth of fuel for landing problems at the Coast Guard station, and you need to have 30 minutes’ worth of fuel to remove the crewman from the boat. You have to create a plan for extracting the crew member. When would you leave and why? Fully explain your answer.
PLEASE EXPLAIN WELL
Mathematics
1 answer:
Alborosie2 years ago
4 0

The helicopter has to leave at 1:30 pm to meet the boat after 2 hours at the meeting point.

<h3>What is Speed ?</h3>

Speed is the distance covered by an object in a given amount of time.

It is measured in km/h or m/h.

According to the data in the question

If the boat goes to the station ,

Speed of the boat = 10mph

it will take 400/10 = 40 hours.

The helicopter has 6600 lbs of fuel.

For the 30 minutes to remove the fisherman and the 1 hour more fuel is needed, that will consume

1.5 *1200 = 1800 lbs of fuel.

the helicopter now has

6600-1800

= 4800 lbs of fuel for flying.

This will give it 4 hours of flying time as

4800 lbs/1200 lbs per hour

it can only fly one way for 2 hours at 150 mph

= 300 miles distance from the station.

The boat is at 400 miles

boat needs to reach the meeting point 300 miles away from the station.

which is 100 miles from where it is now

100/10 = 10 hours

the boat will need 10 hours to go to the meeting point.

To meet the boat , which will take 10 hours the helicopter must start flying after 8 hours as it will also take 2 hrs

So 8 hours from 5:30 am will be 1:30 pm

The helicopter has to leave at 1:30 pm to meet the boat after 2 hours at the meeting point.

To know more about Speed

brainly.com/question/7359669

#SPJ1

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The point-slope form of the equation for the line is ...

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