Given :
- A = {x: 2x² + 3x - 2 = 0 }
- B = {x : x² + 3x - 4 = 0 }
To find :
Solution :-
<u>The </u><u>first </u><u>set </u><u>is </u><u>,</u>
- A ={x : 2x² + 3x - 2 = 0}
<u>Solving</u><u> </u><u>the </u><u>Quadratic</u><u> equation</u><u> </u><u>,</u>
- 2x² + 3x - 2 = 0
- 2x² + 4x - x - 2 = 0
- 2x( x + 2) -1( x + 2 ) = 0
- (2x -1) ( x + 2) = 0
- x = 0.5 , -2
<u>Hence</u><u> </u><u>,</u>
<u>The </u><u>second</u><u> </u><u>set </u><u>is </u><u>,</u>
- B ={ x :x² + 3x - 4 = 0 }
<u>Solving</u><u> the</u><u> Quadratic</u><u> equation</u><u> </u><u>,</u>
- x² + 3x - 4 = 0
- x² + 4x - x - 4 = 0
- x( x + 4)-1 ( x +4) = 0
- (x + 4) ( x -1) = 0
- x = 1 , -4
<u>Hence</u><u> </u><u>,</u>
<u>Now </u><u>,</u>
- A U B = { 0.5 , 1 , 4 , -2}
- A Π B = {∅ }
Since AΠ B is a null set , hence ,
Answer: $4.83
Step-by-step explanation:
you do 145/30=4.8333
<u>Can i please have brainliest, if not thats alright</u>
<u>Have a good day</u>
Hello from MrBillDoesMath!
Answer:
@ = pi/3 (or 60 degrees) or @ = 7 pi/3 (or 420 degrees)
Discussion:
Let "@' denote the angle "theta". We are asked to find @ in the interval [0, 4 pi)
where
4cos(@) - 2 = 0. Adding 2 to both sides
4 cos(@) - 2 +2 = 2 =>
4 cos(@) = 2 Divide both sides by 4
cos(@) = 2/4 = 0.5
This implies that @ = pi/3 (or 60 degrees) or @ = (pi/3 + 2pi) = 7 pi/3 (or 420 degrees)
Thank you,
MrB
Answer:
2pier is the formula for circumference
Step-by-step explanation:
