For each day , select the number of hours worked. HELP! THE ANSWERS ARE IN THE BOX THINGY!

a gardener plants 36 tomato vines in 2 hours at this rate how many tomato Vines can the gardener plant in 5 hours

Bumek [7]

The Correct Answer is 90

First find out how many in 1 hour so do

36÷2 to get 18

(36 Tomato Vines in 2 Hours)

Then do

18×5 to get 90

6 0

3 years ago

Ruby conducted a survey and found the 5/6 of her classmates have a pet and 2/3 of those pets are dogs.what fraction of her class

Pie

To determine the fraction of her classmates with dogs as pets, we simply multiply the two given fractions based from the survey.

Pets = (2/3)(5/6) = 5/9

Thus, there are 5/9 of Ruby;s car.

5 0

3 years ago

Three shirts and two pairs of pants cost $40. Four shirts and one pair of pants cost $37.50. How much does one shirt cost?

taurus [48]

Answer:

d, 700

Step-by-step explanation:

it's the only one that makes sense

4 0

3 years ago

Of the entering class at a college, % attended public high school, % attended private high school, and % were home schoole

Veronika [31]

Answer:

(a) The probability that the student made the Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

A = a student attended public high school

B = a student attended private high school

C = a student was home schooled

D = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

$P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})$

Compute the probability that the student made the Dean's list as follows:

$P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)$

$=(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655$

Thus, the probability that the student made the Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D)}$

$=\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411$

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

$P(C^{c}|D^{c})=1-P(C|D^{c})$

$=1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185$

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0

2 years ago

You purchased a smartphone using your Visa® credit card. Your Visa has a monthly finance charge of 2.5% beginning the first of t

polet [3.4K]

Answer is a idk the math teacher is not a teacher or teacher that she is going through so I am going

3 0

3 years ago

For each day , select the number of hours worked. HELP! THE ANSWERS ARE IN THE BOX THINGY!​

For each day , select the number of hours worked. HELP! THE ANSWERS ARE IN THE BOX THINGY!