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Helen [10]
2 years ago
5

Solve ln(6x-1) = -4 for x

Mathematics
2 answers:
Reika [66]2 years ago
5 0

Answer: Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x

=

−

1

2

Decimal Form:

x

=

−

0.5

Step-by-step explanation:

mars1129 [50]2 years ago
4 0

Answer:

answer,:d=-95

Step-by-step explanation:

6

2

−

+

4

=

0

6x^{2}-x+4=0

6x2−x+4=0

=

6

a={\color{#c92786}{6}}

a=6

=

−

1

b={\color{#e8710a}{-1}}

b=−1

=

4

c={\color{#129eaf}{4}}

c=4

=

−

(

−

1

)

±

(

−

1

)

2

−

4

⋅

6

⋅

4

√

2

⋅

6

x=\frac{-({\color{#e8710a}{-1}}) \pm \sqrt{({\color{#e8710a}{-1}})^{2}-4 \cdot {\color{#c92786}{6}} \cdot {\color{#129eaf}{4}}}}{2 \cdot {\color{#c92786}{6}}}

x=2⋅6−(−1)±(−1)2−4⋅6⋅4

4

Simplify

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Simplify the expression.<br><br> [(11 - 4)^3]^2 ÷ (4 + 3)^5
MAXImum [283]

Answer:

<h2>7</h2>

Step-by-step explanation:

\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7

5 0
3 years ago
The table below shows the number of shoppers at Jacob's store over a period of five months:
Olin [163]

We are given table

Month :         1     2        3         4         5

Shoppers:   50  250   1250   6250  3250

so, we have

first term =50

a_1=50

Second term =250

a_2=250

Third term =1250

a_3=1250

a_4=6250

a_5=31250

now, we can find ratios

\frac{a_2}{a_1} =\frac{a_3}{a_2}=\frac{a_4}{a_3}=\frac{a_5}{a_4}=5

we can see that all ratios are same and 5

so, this is exponential

so, option-D..........Answer



3 0
3 years ago
Read 2 more answers
What is 2^4 divided by (4/10 times 2)
hichkok12 [17]

Answer:

20

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find an equation of the line satisfying the given conditions Through (6,4); perpendicular to 3X + 5Y =38
Katyanochek1 [597]
To answer this, we will need to know:

• The slope of the equation we are trying to get
• The point it passes through using the 

First, we will need to find the slope of this equation. To find this, we must simplify the equation 3x+5y=38 into y=mx+b form. Lets do it!

3x+5y=38
= 5y = -3x+38 (Subtract 3x from both sides)
= y= -\frac{3}{5}x+ \frac{38}{5} (Divide both sides by 5) 

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is \frac{5}{3}. 

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

\frac{y-y _{1} }{x- x_{1} }=m

Substituting values, we find that:

\frac{y-4}{x-6}= \frac{5}{3}

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that: 

y= \frac{5}{3}x-6 , which is our final answer.

Thank you, and I wish you luck.
8 0
3 years ago
Read 2 more answers
Question 18 (5 points)
Nitella [24]
Yea you got this the answer is easy
8 0
2 years ago
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