All categories

2 years ago

Solve ln(6x-1) = -4 for x

Mathematics

2 answers:

Reika [66]2 years ago

5 0

Answer: Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

−

Decimal Form:

−

0.5

Step-by-step explanation:

mars1129 [50]2 years ago

4 0

Answer:

answer,:d=-95

Step-by-step explanation:

−

6x^{2}-x+4=0

6x2−x+4=0

a={\color{#c92786}{6}}

a=6

−

b={\color{#e8710a}{-1}}

b=−1

c={\color{#129eaf}{4}}

c=4

−

(

−

)

(

−

)

−

⋅

√

⋅

x=\frac{-({\color{#e8710a}{-1}}) \pm \sqrt{({\color{#e8710a}{-1}})^{2}-4 \cdot {\color{#c92786}{6}} \cdot {\color{#129eaf}{4}}}}{2 \cdot {\color{#c92786}{6}}}

x=2⋅6−(−1)±(−1)2−4⋅6⋅4

Simplify

You might be interested in

Pls help, for 10 points!

Masteriza [31]

Answer:

I think 9 but dont quote me on it

3 0

2 years ago

Read 2 more answers

A typical sugar cube has an edge length of 1.00 cm. Imagine you have a cubical box that contains a mole of sugar cubes, perfectl

alisha [4.7K]

Answer:

844368.7 m

Step-by-step explanation:

We are given that a typical sugar cube has an edge length of 1.00 cm.

We have to find the edge length of the box in meters.

Edge length of sugar cube=1 cm = $10^{-2}m$ ( $1 cm=\frac{1}{100}m$ )

Volume of a sugar cube= $side\times side\time side=(10^{-2})^3=10^{-6}m^3$

1 mole of sugar= $6.02\times 10^{23}units$

Volume of 1 unit= $10^{-6} m^3$

Volume of $6.02\times 10^{23}$ units= $6.02\times10^{23}\times 10^{-6}=6.02\times 10^{17} m^3$

Volume of box=1 mole of sugar= $6.02\times 10^{17} m^3$

Edge length of box= $\sqrt[3]{6.02\times 10^{17}}=844368.7 m$

6 0

2 years ago

to communication companies offer calling plans with company X it cost $0.35 to connect and then $0.05 for each minute with compa

Mama L [17]

Answer:

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

Step-by-step explanation:

Given:

Cost of X company = $\$ 0.35+(\$0.05\times 1 \ minute)$

Cost of Y Company = $\$ 0.15+(\$0.04\times 1 \ minute)$

for n minutes

Cost of X company for n minutes = $\$ 0.35+(\$0.05\times n \ minute)$

Cost of Y Company for n minutes = $\$ 0.15+(\$0.04\times n \ minute)$

Difference for n minutes we get by Subtracting Cost of Y Company for n minutes by Cost of X company for n minutes

Difference for n minutes = $(\$ 0.2+\$ 0.01n)$ = $(0.2+0.01n)\times 10^2 \ cents$

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

6 0

2 years ago

What is 12% of 1350?

antoniya [11.8K]

162 is the answer to your question siskjsskjajanajajajsjskskaiw

3 0

2 years ago

Read 2 more answers

find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}

inn [45]

Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2 and x" = [10 - √64]/2

x' = (10+12)/2 and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity

6 0

3 years ago