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Rudik [331]
2 years ago
15

Using the table, which value from the domain corresponds to a range value of 3?

Mathematics
2 answers:
ozzi2 years ago
8 0
We know that

A range value of 3 that means 
that the value of y is 3

<span>observing the table we see that for y = 3  the value of x is 0
therefore
the value of the domain for the range 3 is 0

the answer is
0

</span>
Vaselesa [24]2 years ago
4 0
Its B) 0   
Hope it Helps
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Answer:

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three zebras are chilling in the desert. suddenly a lion attacks. each zebra is sitting on a corner of an equally length triangl
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Probability that no zebras collide is 0.25

The zebras are represented as z1, z2 and z3.

Z1 to B, Z2 to C, and Z3 to A come first = (\frac{1}{2})^3

Following that, z1 to C, z2 to A, and z3 to B = (\frac{1}{2})^3

Consequently, the likelihood of no collision is 2×1/8 = 0.25.

<h3>What are the types of probability distributions ?</h3>

Discrete and continuous probability distributions are the two main categories in which probability distributions fall. There are numerous varieties of probability distributions within each category.

  • The number of favorable outcomes of an event divided by the total number of possible outcomes of an event can be used to calculate the probability of an event.
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4 0
1 year ago
The number of text messsages that teenagers send per month is normally
ki77a [65]

Answer:

z=\frac{4415-3400}{450}=2.26

And the explanation of this number is:"The number of text messages for Kendra it's 2.26 deviations above the mean"

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Calculate the z score

Let X the random variable that represent the number of text messages per month, and for this case we know the distribution for X is given by:

X \sim N(3400,450)  

Where \mu=3400 and \sigma=450

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

z=\frac{4415-3400}{450}=2.26

And the explanation of this number is:"The number of text messages for Kendra it's 2.26 deviations above the mean"

6 0
3 years ago
You want to enlarge a 4 x 5 inch photo to fit into a 1 inch wide frame
skelet666 [1.2K]

The 4•x by 5•x inner dimensions of the 53 inches outer perimeter picture frame, the 1 inch wide frame and the 4 × 5 inch picture to be enlarged, gives;

a. The outer perimeter equation is presented as follows;

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<h3>Which method can be used to write the equation and find the scale factor?</h3>

The dimensions of the photo = 4 × 5 inch

Width of the frame = 1 inch

Outer perimeter of the frame = 53 inches

The width of the inside of the picture frame = 4•x

The height of the inside of the picture frame = 5•x

a. The equation for the outer perimeter of the picture frame is therefore;

2 × (4•x + 1 + 1) + 2 × (5•x + 1 + 1) = 53

Which gives;

2 × (4•x + 2) + 2 × (5•x + 2) = 53

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A simplified equation for the outer perimeter of the picture frame is therefore;

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b. Solving the above equation, we have;

18•x + 8 = 53

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Therefore;

x = 45 ÷ 18 = 2.5

x = 2.5

The width and height of the picture frame are therefore;

Width = 4•x = 4 × 2.5 = 10

Height = 5•x = 5 × 2.5 = 12.5

Which gives;

Width = 10 inches

Height = 12.5 inches

The enlargement factor, sf, is given by the ratio of a side of the picture frame to a side of the picture as follows;

sf = 12.5/5 = 2.5

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