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liraira [26]
3 years ago
11

to angie's ladder was 22 feet tall above the ground lying against the wall of her house.the base of the ladder was 5 feet tall.w

hat was the slope? ASAP PLEASE ANSWER THIS :(

Mathematics
1 answer:
Talja [164]3 years ago
3 0

Answer:


Step-by-step explanation:

Okay, so attached is a diagram of the triangle we are solving. Because buildings are almost always perpendicular (90 degrees) to the ground, it is a right triangle.

You can now use the pythagorean theorem with the sides to fill in the other side:


a^2+ b^2= c^2

5^2 + b^2= 22^2

25+b^2=484

b^2= 459

b=21.42


Okay, so for slope you need 2 points- think of the wall as your y axis, and the ground as your x axis. The ladder is the line.

Your first point is (-5,0) because the bottom of the ladder is touching the ground (no y movement) and the bottom of the ladder is 5 feet from the base of the wall and ground (origin).

The second point is going to be (0, 21.42) because that is the height of the wall where the ladder is touching (x is at origin). The 21.42 is positive, because you can't have negative height.

Okay so far? :)

(-5,0) and (0, 21.42)

(x1, y1) and (x2, y2)

slope= (y2-y1)/(x2-x1)

slope= (21.42-0)/ (0-(-5)) ---- becomes positive

slope= 4.284

(Note: slope could also be negative if you put the ladder on the other side of the wall- 5 would become positive... google "positive vs negative slopes" for more info)


Hopefully that answers your question!

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\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

Area of shaded region = 34 cm²

\textsf{  \underline{\underline{Steps to solve the problem} }:}

Area of shaded region = Area of bigger rectangle - Area of smaller rectangle.

Area (big) :

\qquad❖ \:  \sf \:13 \times 6

\qquad❖ \:  \sf \:78 \:  \:c m {}^{2}

Area (small) :

\qquad❖ \:  \sf \:11 \times 4

\qquad❖ \:  \sf \:44 \:  \: cm {}^{2}

Area of shaded region :

\qquad❖ \:  \sf \:78 - 44

\qquad❖ \:  \sf \:34 \:  \: cm {}^{2}

\qquad \large \sf {Conclusion}  :

Area of shaded region = 34 cm²

8 0
2 years ago
Assume the following triangles are similar. Find the scale factor and the lengths of the missing sides.
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Answer:

If two figures are similar, then the correspondent sides are related by a constant factor.

For example, if the base of one side of one of the figures has a length L, then the correspondent side of the other figure has a length k*L where k is the scale factor.

Let's start with the two left triangles.

In the smaller one the base is 5, and the base of the other triangle is 15.

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The scale factor is 3.

Then we will have that:

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For the other two triangles, the base of the smaller triangle is 12, while the base of the larger triangle is 20.

Then we will have the relation:

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The scale factor is 5/3

This means that the unknown side b is given by:

b*(5/3) = 15

b = (3/5)*15 = 3*3 = 9

b = 9.

5 0
3 years ago
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