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2 years ago

Help please I am dumb and don’t fell like taking this test

Mathematics

2 answers:

lora16 [44]2 years ago

7 0

Answer:

75.4

Step-by-step explanation:

UkoKoshka [18]2 years ago

5 0

Answer:

I do not know the answer to this question. Ask "LucasPeed"

Step-by-step explanation:

If you need anymore help, ask Brainly. Have a nice day!

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Bubble algae cells can grow up to 5 cm in diameter. Calculate the surface area : volume ratio of this cell.

Mars2501 [29]

Answer:

6:5

Step-by-step explanation:

Bubble algae cells can grow up to 5 cm in diameter. Calculate the surface area : volume ratio of this cell.

The algae is spherical in nature

Volume of the algae =4/3 pi r³

Volume of the algae = 4/3×pi×2.5³

Volume of the algae = 62.5/3 pi

Surface area = 4pi r²

Surface area = 4pi ×2.5²

Surface area = 25pi

Taking their ratio

surface area : volume ratio

= 25pi:62.5/3 pi

= 25 × 3/62.5

= 1.2

Hence the required ratio is 12/10 which is 6:5

4 0

3 years ago

PLEASE HELP ASAP!!! Explain, thank you-

Nat2105 [25]

Answer:

The answer to your question is: $\sqrt[4]{2^{3} } + 1$

Step-by-step explanation:

$\frac{1}{\sqrt[4]{2- 1}} x \frac{\sqrt[4]{2^{3}}+ 1 }{\sqrt[4]{2^{3}} + 1} = [tex]\frac{\sqrt[4]{2^{3}}+ 1 }{2 - 1}$

= $\sqrt[4]{2^{3} } + 1$

6 0

3 years ago

Point K is on line segment JL. Given KL = 2x – 2, JL = 4x + 9, and

sergeinik [125]

Answer:

JL = 21

Step-by-step explanation:

Given that K is on line segment JL, therefore:

KL + JK = JL (according to segment addition postulate)

KL = 2x - 2

JK = 5x + 2

JL = 4x + 9

Thus:

$(2x - 2) + (5x + 2) = (4x + 9)$

Solve for x

$2x - 2 + 5x + 2 = 4x + 9$

$2x +5x - 2 + 2 = 4x + 9$

$7x = 4x + 9$

Subtract 4x from both sides

$7x - 4x = 4x + 9 - 4x$

$3x = 9$

Divide both sides by 3

$\frac{3x}{3} = \frac{9}{3}$

$x = 3$

Find the numerical length of JL

$JL = 4x + 9$

Plug in the value of x

$JL = 4(3) + 9 = 12 + 9 = 21$

7 0

2 years ago

-10 = 2 – 21 <br> Solve for the variable

Arturiano [62]

-10=-19 is the answer goodluck

5 0

2 years ago

In a right triangle sin A=

kherson [118]

Answer:

$sinA=\frac{opposite}{hypotenuse}$

Step-by-step explanation:

Soh-cah-toa is a great way to remember:

$sin=\frac{opposite}{hypotenuse}\\ cin=\frac{adjacent}{hypotenuse}\\ tan=\frac{opposite}{adjacent}$

You just remember the first letters : sine= opposite/hypotenuse , for example.

6 0

3 years ago

Read 2 more answers