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3 years ago

6

The functions f(x) and g(x) are shown on the graph.

1 answer:

Grace [21]3 years ago

6 0

Answer:

I believe the answer is D.

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Carson throws a ball upward into the air the height of the ball is determined by h(t)= -16t^2 +60t+ 5.5. what is the height in f

Alex777 [14]

The ball was initially thrown from a height of 5.5 feet and 5.5 is y intercept that it throm from 5.5 feet.

6 0

3 years ago

Please help with 6 and 7

Ilya [14]

Answer:

6. The number is $-5$

7. The two numbers are $10$ and $11$

Step-by-step explanation:

Question six can be re-worded to create the following expression:

$-2=\frac{4x+10}{5}$

Solve for x to find the number:

$-2=\frac{4x+10}{5}\\-10=4x+10\\-20=4x\\\frac{-20}{4} = x\\-5 = x$

Question seven can be solved by first listing the constraints (assuming x is smaller than y):

x and y are less than 20
$x + 1 = y$
$3x - 8 = 2y$

To get the numbers, we can create a system of linear equations. First, solve for $y$ in each expression:

$y = x+1$

$2y = 3x-8\\y = \frac{3}{2}x - 4$

Solve for $x$ :

$x+ 1 = \frac{3}{2}x - 4\\x + 5 = \frac{3}{2}x\\5 = \frac{3}{2}x - x\\5 = \frac{1}{2}x\\10 = x$

Solve for $y$ :

$y = x + 1\\y = 10 + 1\\y= 11$

4 0

1 year ago

Read 2 more answers

Perpendicular to y=1/2-1, x-intercept at4

AlexFokin [52]

Answer:

it would be Y= -2x+4

Step-by-step explanation:

To begin, we know that the b value is 4, because that is the x-intercept that is information given, so we can atomatically put that in.

Next we need to find the m value, which can be found by knowing the rules of a perpendicular eqution. to change it you must change the 1/2 and flip the equation and change the signs

soooooo 1/2 would change into 2/1 which is 2 and we would addd the negative sign so

Y=-2x+4

8 0

3 years ago

Read 2 more answers

13 please I have no idea what the steps for this is

Ilya [14]

Answer:

UV=142

Step-by-step explanation:

21x-13=10x+31

+13 +13

21x=10x+44

-10x=-10x

11x=44

÷11 ÷11

x=4

now substitute 4 in place of x (only have to solve one)

21(4)-13= 71

now multiply your answer by 2

71×2=142

6 0

3 years ago

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

6 0

3 years ago