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2 years ago

An equilateral triangle is similar to a scalene triangle. True or False

Mathematics

1 answer:

san4es73 [151]2 years ago

8 0

Answer:

False.

Step-by-step explanation:

All the sides of an equilateral triangle are equal.

None of the sides of a scalene triangle are equal to each other.

Therefore, an equilateral triangle is not similar to a scalene triangle.

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3x + 3 X + 8 What is the perimeter of each polygon?

Ganezh [65]

Answer:

D. 60

Step-by-step explanation:

4(3x + 3) = 5(x + 8) 12(4) + 12 5(4) + 40

12x + 12 = 5x + 40 48 + 12 20 + 40

-5x -5x 60 60

7x + 12 = 40

-12 -12

7x = 28

x = 4

6 0

3 years ago

The water level of a certain body of water is changing at a rate of W(t)=3/4cos(4-t/2) inches per hour, where t represents hours

Leni [432]

Answer:

The answer is below

Step-by-step explanation:

a) The integral $\int\limits^{10}_{1 } {W(t)} \, dt$ means the total change in level of water in inches from 1 am to 10 am. That is the water level change measured in inches between 1 am and 10 am

b) 7 pm is represented as t = 19 hours, while midnight is represented as t = 24 hours, hence the water level change between 7 pm and midnight is:

$\int\limits^{24}_{19 } {W(t)} \, dt\\\\$

c) Using casio calculator to evaluate the integral gives:

$\int\limits^{24}_{19 } {W(t)} \, dt\\\\$ = 2.54 inches

D) The total daily change in water level = $\int\limits^{24}_{0 } {W(t)} \, dt\\\\$ = 0.35 inches

8 0

2 years ago

A shirt is on sale for 30% off the original price of $85.00.

wlad13 [49]

Answer:

59.5

Step-by-step explanation:

30% of 85 is 25.5

85-25.5=59.5

5 0

2 years ago

What is the next number in the sequence? 3, 6, 12, , ... place an x by the pattern of the sequence. add 2 subtract 2 times 2?

ch4aika [34]

3,6,12...

this is a geometric sequence with a common ratio of 2. That means u multiply each term by 2 to find the next term.

start with 3
3 * 2 = 6
6 * 2 = 12
12 * 2 = 24...this would be ur next term

so ur answer is : multiply by 2

8 0

3 years ago

Evaluate the line integral c y3 ds, c.x = t3, y = t, 0 â‰¤ t â‰¤ 3

Temka [501]

$\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\int_{t=0}^{t=3}t^3\sqrt{1^2+(3t^2)^2}\,\mathrm dt=\int_0^3t^3\sqrt{1+9t^4}\,\mathrm dt$

Take $u=1+9t^4$ so that $\mathrm du=36t^3\,\mathrm dt$ . Then

$\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\frac1{36}\int_{u=1}^{u=730}\sqrt u\,\mathrm du=\frac{730^{3/2}-1}{54}$

7 0

3 years ago