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GenaCL600 [577]
2 years ago
13

HELP! THIS IS DUE TODAY, and i will mark brainlest!

Mathematics
1 answer:
Tomtit [17]2 years ago
3 0

Answer:

the answer is c because if you think about it, it has an input and put its just not a function.

Step-by-step explanation:

hope this helps if so you could join a meeting if you'd like

You might be interested in
Solve for n.<br><br> n + 1 = 4(n – 8)
kolezko [41]
N + 1 = 4(n – 8)
Use distributive property for this part: 4(n – 8) ----> 4n - 32

n + 1 = 4n - 32

Get the variable on one side: 

n + 1 = 4n - 32
-n         -n

1= 3n - 32

Get the variable on its own:

1= 3n - 32 
+32       +32

33 = 3n

Divide by 3 on both sides: 

33/3 = 3n/3

n = 11



7 0
3 years ago
The diameter of a coin is 26mm. Mathew lined up 56 coins from the left end of his desk to the right end of his desk. What is the
Ne4ueva [31]

Answer:

Your answer is 145.6

Step-by-step explanation:

First multiply 56 and 26 which then you get 1456mm then divide the length value by ten and then you get 145.6.

Hope I helped!

5 0
2 years ago
The Cubs have won
Naily [24]

First you need to figure out the games the Cubs lost. 11-7=4, so they lost 4 games.

Now you must plug in the ratio of games lost to games played. You know they lost 4 games and played 11, so the ratio would be 4:11.

I hope you find this helpful :)

4 0
3 years ago
Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangl
Whitepunk [10]

Answer:

<u>24 meters</u> is the width of the original rectangle.

Step-by-step explanation:

Given:

Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangle is 30 meters and the reduced rectangle has a length of 9 meters.

Now, to get the width of original rectangle.

The reduced rectangle's perimeter = 30 meters.

The reduced rectangle's length = 9 meters.

Now, we find the width of reduced rectangle by using formula:

Let the width of reduced rectangle be x.

Perimeter=2\times length+2\times width

30=2\times 9+2\times x

30=18+2x

<em>Subtracting both sides by 18 we get:</em>

<em />12=2x<em />

<em>Dividing both sides by 2 we get:</em>

6=x\\\\x=6\ meters.

The width of reduced rectangle = 6 meters.

Now, to get the width of original rectangle:

Let the width of original rectangle be w.

<em>As given, the perimeter of the original rectangle = 120 meters.</em>

<em>And, the perimeter of reduced rectangle is 30 meters and its width is 6 meters.</em>

<em>So, 30 is equivalent to 6.</em>

<em>Thus, 120 is equivalent to </em>w.<em />

Now, to get the width using cross multiplication method:

\frac{30}{6}=\frac{120}{w}

<em>By cross multiplying we get:</em>

<em />30w=720<em />

<em>Dividing both sides by 30 we get:</em>

<em />w=24\ meters.<em />

<em>The width of original rectangle = 24 meters.</em>

Therefore, 24 meters is the width of the original rectangle.

6 0
3 years ago
Read 2 more answers
Find the area<br><br> A. 50in<br> B. 60in<br> C. 50in2<br> D. 60in2
ludmilkaskok [199]

Answer:

The answer is 60in^2

Step-by-step explanation:

5 0
3 years ago
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