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3 years ago

How do I do this? Help!

Mathematics

1 answer:

Hitman42 [59]3 years ago

4 0

Notice the picture below

you have two triangles, and you have the opposite and adjacent sides

thus, recall your SOH CAH TOA $\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}$

anyhow.. the one that has only
the angle
the opposite
and the adjacent

is Ms Tangent, so lets ask her some

$\bf tan(29^o)=\cfrac{x}{y}\implies y\cdot tan(29^o)=x
\\\\\\
tan(25^o)=\cfrac{x}{100-y}\implies (100-y)tan(25^o)=x\\\\
-----------------------------\\\\
x=x\qquad thus\qquad y\cdot tan(29^o)=(100-y)tan(25^o)$

solve for "y"

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