I did my math and I think 41 minuets but are u adding or subracting
Mode = number which appears the most
The mode for your question is 5
The factors of 50a³ are 1, 2, 5, 10, 25, 50,
and their products with a, a² and a³ .
The factors of 10a² are 1, 2, 5, 10,
and their products with 'a' and a² .
Their common factors are 1, 2, 5, 10,
and their products with 'a' and a².
Their greatest common factor is 10a² .
(Another way to spot it, easily, is to remember this helpful factoid:
If the smaller number is a factor of the larger number,
then the smaller number is their greatest common factor.
Using the greatest common factor, then . . .
50a³ + 10a² = 10a²(5a + 1) .
Answer:
-88
Step-by-step explanation:
Let N(x) be the number of students at NMS for a certain number of years.
Let S(x) be the number of students at SMS for a certain number of years.
Let x be the number of years.
N(x)=1240-25x
S(x)=800-30x
When # of students is equal, N(x)=S(x). Therefore, we are looking for the value of x (# of years) when 1240-25x=800-30x
Subtract 1240 from each side
-25x=-440-30x
Add 30x
5x=-400
x=-88 years
Check your numbers.