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xz_007 [3.2K]
3 years ago
10

At lunch Claire is drinking her juice out of an aluminum can She claims that if the radius of the can is doubled, the volume of

the can will be greater than if the height of the can is doubled
Mathematics
1 answer:
OLga [1]3 years ago
6 0

Answer:

True

Step-by-step explanation:

Can is shaped in the form of a cylinder :

Volume, V of a cylinder = πr²h

Volume if radius is doubled and height remains the same :

r = 2r

V = π(2r)²h

V = 4πr²h

Volume if height is doubled and radius remains the same ;

V = πr²h

If h = 2h

V = 2πr²h

Radius doubled ; V = 4πr²h

Height doubled ; V = 2πr²h

Hence, volume of can is greater with Radius doubled than with height doubled.

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Answer:

Shen served 32 orders, Aldo served 16 orders and Heather served 9 orders

Step-by-step explanation:

Let S represent Shen, A, Aldo and H, Heather

Now, let's interpret the question

Shen served 2 times as many as Aldo, this gives:

S = 2A          ...eq 1

Aldo served 7 more orders than Heater

A = 7 + H     ... eq 2

Slot in the value of A in eq 1

Therefore,

S = 2 (7 + H)

Expand the bracket

S = 14 + 2H

Shen, Heather and Aldo served a total of 57 orders

S + A + H = 57

Slot in the values of S and A

(14 + 2H) + (7 + H) + H = 57

14 + 2H + 7 + H + H = 57

Collect like terms

14 + 7 + 2H + H + H = 57

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4H = 57 - 21

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Substitute the value of eq 2

A = 7 + H

A = 7 + 9

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Substitute the value of A in eq 1

S = 2A

S = 2(16)

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Therefore, Shen served 32 orders, Aldo served 16 orders and Heather served 9 orders

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