Ask question

Ask question

All categories

3 years ago

10

Sue purchased a $30,000 life insurance policy at the price of $24 for each $1000 of coverage. If she pays the premium in 12 mont

hly installments, how much is each installment?

1 answer:

Inessa [10]3 years ago

3 0

Cost of life insurance is $30000 at a price of for each $24 for each $1000 of coverage.

Cost = $\frac{24}{1000}\times30000$

= $720

Premium is paid each month then it becomes $\frac{720}{12}=60$

=$60

You might be interested in

Stats. can someone help?

artcher [175]

Answer:

you should try picto math it very helpful!

Step-by-step explanation:

5 0

3 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

Smiths bike shop rents bikes for $10

Trava [24]

10+(4x3)= $22 (How much she rent the bike for)

3 0

2 years ago

The triangles below are similar. Find x.

Anni [7]

Answer: 105

Step-by-step explanation:

Corresponding sides of similar triangles are proportional, so

$\frac{x}{14}=\frac{97.5}{13}\\\\=\frac{x}{14}=7.5\\\\x=\boxed{105}$

8 0

2 years ago

The perimeter of a triangle is 93 ft. Side a of the triangle is twice as long as side b. Side c is 3 ft longer than side a. Find

Sunny_sXe [5.5K]

The length of side a is 36 feet and side b is 18 feet and side c is 39 feet

<em><u>Solution:</u></em>

Given that perimeter of triangle is 93 feet

The three sides of triangle are a, b, and c

<em><u>Given that Side a of the triangle is twice as long as side b</u></em>

side a = 2 times side b

a = 2b

$b = \frac{a}{2}$ ---- eqn 1

<em><u>Given that Side c is 3 ft longer than side a</u></em>

side c = 3 + side a

c = 3 + a ------ eqn 2

<em><u>The perimeter of triangle is given as:</u></em>

p = a + b + c

Where a, b, c are the length of sides of triangle

Substitute eqn 1 and eqn 2 in above formula

$p = a + \frac{a}{2} + 3 + a$

Given that perimeter = 93

$93 = a + \frac{a}{2} + 3 + a\\\\93 = \frac{2a + a + 6 + 2a}{2}\\\\93 \times 2 = 2a + a + 6 + 2a\\\\186 = 5a + 6\\\\5a = 186 - 6\\\\5a = 180\\\\a = 36$

Thus length of side a = 36 feet

<em><u>Length of side b :</u></em>

from eqn 1

$b = \frac{36}{2} = 18$

b = 18 feet

<em><u>Length of side c:</u></em>

From eqn 2,

c = 3 + 36 = 39

c = 39 feet

Thus length of side a is 36 feet and side b is 18 feet and side c is 39 feet

6 0

3 years ago