Answer:
![\large\boxed{g\bigg(f(2)\bigg)=11}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bg%5Cbigg%28f%282%29%5Cbigg%29%3D11%7D)
Step-by-step explanation:
![f(x)=3x-2,\ g(x)=x^2-5\\\\g\bigg(f(2)\bigg)=?\\\\\bold{STEP\ 1:}\\\text{Calculate}\ f(2).\\\text{Substitute}\ x=2\ \text{to}\ f(x):\\\\f(2)=3(2)-2=6-2=4\\\\\bold{STEP\ 2:}\\\text{Substitue}\ x=4\ \text{to}\ g(x):\\\\g(4)=4^2-5=16-5=11](https://tex.z-dn.net/?f=f%28x%29%3D3x-2%2C%5C%20g%28x%29%3Dx%5E2-5%5C%5C%5C%5Cg%5Cbigg%28f%282%29%5Cbigg%29%3D%3F%5C%5C%5C%5C%5Cbold%7BSTEP%5C%201%3A%7D%5C%5C%5Ctext%7BCalculate%7D%5C%20f%282%29.%5C%5C%5Ctext%7BSubstitute%7D%5C%20x%3D2%5C%20%5Ctext%7Bto%7D%5C%20f%28x%29%3A%5C%5C%5C%5Cf%282%29%3D3%282%29-2%3D6-2%3D4%5C%5C%5C%5C%5Cbold%7BSTEP%5C%202%3A%7D%5C%5C%5Ctext%7BSubstitue%7D%5C%20x%3D4%5C%20%5Ctext%7Bto%7D%5C%20g%28x%29%3A%5C%5C%5C%5Cg%284%29%3D4%5E2-5%3D16-5%3D11)
$20 hai
The answer is $23.00
Answer:
Table A and Graph B
Step-by-step explanation:
It is Graph B because of the equation's slope which is 3. This 3 is represented as
as a slope or as a "rise over run", this means that the graph goes up by 3 units while going right by 1 unit.
It is Table A because the points in the graph match with the points which Graph B goes through.
Answer:The prime factorization of 196 is 196 = 2 × 2 × 7 × 7 and can be represented as 196 = 2 2 × 7 2 using exponents.
Step-by-step explanation:
can u report me snd dont ask y
<h3>
Answer: D) -3</h3>
Explanation:
Recall that y = f(x) since both are outputs of a function.
If k = 2, then f(x) = 2 leads to y = 2 being a horizontal line drawn through 2 on the y axis. This horizontal line only crosses the cubic curve at one spot. The same can be said if k = 0 and k = -2. So we can rule out choices A,B,C.
On the other hand, if k = -3, then f(x) = -3 has three different solutions. This is because the horizontal line through -3 on the y axis crosses the cubic at 3 different intersection points.