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fomenos
4 years ago
5

Need help, please answer!!!

Mathematics
1 answer:
RoseWind [281]4 years ago
7 0
Find urban know first
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|-4| + |-5| i need help!!!
iren2701 [21]

Answer:

9

Step-by-step explanation:

The absolute value of any number is just its distance from 0.

-4 is 4 away from 0, so its absolute value is 4.

-5 is 5 away from 0, so its absolute value is 5.

Therefore, the equation is basically just asking what is 4 + 5, which is 9 :D.

4 0
3 years ago
Read 2 more answers
For the spinner above, the probability of landing on black is 1/2, and the probability of landing on red is 1/3. Suppose it is s
saul85 [17]

Answer:

d) The probability spinner will land on black all three times is 1/8

Step-by-step explanation:

The probability of landing on black = 1/2

The probability of landing on red    =  1/3.

Now, if the spinner is spun 3 times.

The probability  it will land on black all three times  

= \textrm{ (The probability of landing on black)}^3

= \frac{1}{2}   \times  \frac{1}{2}  \times  \frac{1}{2}  = \frac{1}{2 \times 2 \times 2 } = \frac{1}{8}

Hence, the probability spinner will land on black all three times is 1/8.

8 0
3 years ago
Algebra 1 Module 2 Topic c Quiz
stiks02 [169]

Step-by-step explanation:

a.

Female fall= 42 (19+37+18=74, 116-74)

Female total= 116 (229-113)

Male spring= 21 (50+16+26, 113-92)

Total fall=58 (40+87+44,229-171)

b.

Fall

8 0
3 years ago
In this data set, what effect does the outlier have on the mean and the median? HELP ASSAPPPP
Georgia [21]
The best choice would be D.
3 0
3 years ago
Use Theorem 7.4.1. THEOREM 7.4.1 Derivatives of Transforms If F(s) = ℒ{f(t)} and n = 1, 2, 3, . . . , then ℒ{tnf(t)} = (−1)n dn
Ugo [173]

Answer:

L\left(te^{2t }sin3t\right)=\frac{6s-12}{(s^2-4s+13)^2}.

Step-by-step explanation:

If F(s)= L{f(t)}

Then L\left\{(t^nf(t)\right\}=(-1)^n\frac{\mathrm{d^n}F(s)}{\mathrm{d^n}s}

L\left\{te^{2t}sin3t\right\}

f(t)=e^{2t}sin3t

L\left\{e^{at}sinbt\right\}=\frac{b}{(s-a)^2+b^2}

Therefore,L\left\{e^{2t}sin3t\right\}=\frac{3}{(s-2)^2+(3)^2}

L\left\{e^{2t}sin3t\right\}=\frac{3}{s^2-4s+13}

L\left\{te^{2t}sin3t\right}=-\frac{\mathrm{d}F(s)}{\mathrm{d}s}

=-\frac{\mathrm{d}e^{2t}sin3t}{\mathrm{d}s}

L\left\{te^{2t}sin3t\right\}

=\frac{3(2s-4)}{(s^2-4s+13)^2}

L\left\{te^{2t}sin3t\right\}=\frac{6s-12}{(s^2-4s+13)^2}.

7 0
4 years ago
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