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vredina [299]
3 years ago
6

What is 3-8 + 2v- v equal to?​

Mathematics
1 answer:
Anettt [7]3 years ago
6 0
If the answer is supposed to be an equation, it should be -5(+)v
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the label on the bottle of vitamin says that each capsule contain 0.5 grams. when check each capsule had 0.505 grams. was that t
Diano4ka-milaya [45]

Answer:

0.505 g is <em>more than</em> the advertised amount by 0.005 g.

Step-by-step explanation:

0.5 = 0.500, so 0.505 is <em>more than</em> the advertised amount.

"Too little" or "too much" is a judgment based on some criteria not specified by the problem statement. Usually a supplier will want to ensure the customer receives full measure, so will adjust the capsule-making machine to provide at least the advertised amount. Whether it is "too little" or "too much" depends on your point of view and the dangers or costs of deviating from the advertised amount.

0.505 - 0.500 = 0.005 . . . . the difference between the actual and advertised amounts, in grams.

8 0
3 years ago
Chesapeake Pizza prepares pizzas with as many as
postnew [5]
Hope I’m not as late but the cost per topping is 80 cents.
4 0
3 years ago
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What is two-fifths of three-sevenths?
kompoz [17]
It's 6/35 because of means multiply and take numerator times numerator and denominator times denominator when you multiply fractions. 2 x 3 = 6 over 5 x 7 = 35. 6/35.
3 0
3 years ago
Please answer the question below (ABOUT VECTORS AND MAGNITUDE)
coldgirl [10]

(a) <em>v</em> appears to have a fixed direction along the positive <em>x</em>-axis. If ||<em>u</em>|| = 150 N, ||<em>v</em>|| = 220 N, then when <em>θ</em> = 30°, you have

<em>u</em> = (150 N) (cos(30°) <em>i</em> + sin(30°) <em>j</em> ) ≈ (129.904 <em>i</em> + 75 <em>j</em> ) N

<em>v</em> = (220 N) (cos(0°) <em>i</em> + sin(0°) <em>j</em> ) = (220 <em>i</em> ) N

(<em>i</em> and <em>j</em> are the unit vectors in the positive <em>x</em> and <em>y</em> directions)

and their sum is

<em>u</em> + <em>v</em> ≈ (349.904 <em>i</em> + 75 <em>j</em> ) N

with magnitude

||<em>u</em> + <em>v</em>|| ≈ √((349.904)² + (75)²) N ≈ 357.851 N ≈ 357.9 N

and at angle <em>φ</em> made with the positive <em>x</em>-axis such that

tan(<em>φ</em>) ≈ (75 N) / (349.904 N)   →   <em>φ</em> ≈ 12.098° ≈ 12.1°

(b) Letting <em>θ</em> vary from 0° to 180° would make <em>v</em> a function of <em>θ</em> :

<em>u</em> = (150 N) (cos(<em>θ</em>) <em>i</em> + sin(<em>θ</em>) <em>j</em> ) = (150 cos(<em>θ</em>) <em>i</em> + 150 sin(<em>θ</em>) <em>j</em> ) N

Then

<em>u</em> + <em>v</em> = ((220 + 150 cos(<em>θ</em>)) <em>i</em> + (150 sin(<em>θ</em>)) <em>j</em> ) N

→   <em>M</em> = ||<em>u</em> + <em>v</em>|| = √((220 + 150 cos(<em>θ</em>))² + (150 sin(<em>θ</em>))²) N

<em>M</em> = √(48,400 + 66,000 cos(<em>θ</em>) + 22,500 cos²(<em>θ</em>) + 22,500 sin²(<em>θ</em>)) N

<em>M</em> = 10 √(709 + 660 cos(<em>θ</em>)) N

(c) As a function of <em>θ</em>, <em>u</em> + <em>v</em> makes an angle <em>α</em> with the positive <em>x</em>-axis such that

tan(<em>α</em>) = (150 sin(<em>θ</em>) / (220 + 150 cos(<em>θ</em>))

→   <em>α</em> = tan⁻¹((15 sin(<em>θ</em>) / (22 + 15 cos(<em>θ</em>)))

(d) Filling in the table is just a matter of evaluating <em>M</em> and <em>α</em> for each of the given angles <em>θ</em>. For example, when <em>θ</em> = 0°,

<em>M</em> = 10 √(709 + 660 cos(0°)) N = 370 N

<em>α</em> = tan⁻¹((15 sin(0°) / (22 + 15 cos(0°))) = 0°

When <em>θ</em> = 30°, you get the same result as in part (a).

When <em>θ</em> = 60°,

<em>M</em> = 10 √(709 + 660 cos(60°)) N ≈ 323.3 N

<em>α</em> = tan⁻¹((15 sin(60°) / (22 + 15 cos(60°))) = 23.8°

and so on.

4 0
3 years ago
:) lol<br><br> lollololol<br> :):):):):):):)
murzikaleks [220]

Answer:

32 m^2

Step-by-step explanation:

First find the volume of the bottom section

V = l * w*h

V = 6 * 2 * 2 = 24 m^2

Then find the volume of the top section in green

The length is 6-4 =2,  the height is 4-2, width is 2

V = = l*w*h = 2*2*2 = 8

Ad the volumes together

V = 24+8 = 32 m^2

6 0
2 years ago
Read 2 more answers
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