Question

What are the factors of x2 − 64?

Answer 1

X^2 - 64 = 
(x + 8)(x - 8) <===

Answer 2

Answer: $(x+8)(x-8)$

Step-by-step explanation:

The given polynomial : $x^2-64$

Since both the terms are perfect square.

Rewrite the above equation in the form of difference of two squares:

$x^2-(8)^2$

Using algebraic formula given below:-

$a^2-b^2=(a+b)(a-b)$

$\Rightarrow\ x^2-(8)^2=(x+8)(x-8)$

Hence, the factors of $x^2-64=(x+8)(x-8)$