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kifflom [539]
3 years ago
14

the compound interest of a sum of money for 1 year and 2 years are rs 450 and rs 945 respectively. find the rate of interest com

pounded yearly and he sum.
Mathematics
1 answer:
frozen [14]3 years ago
3 0

Answer:

The answer is below

Step-by-step explanation:

The compound interest is given by the formula:

A=P(1+\frac{r}{n} )^{nt}

Where A is the final amount, p is the principal (initial amount), r is the rate, t is the number of period and n is the number of times it was compounded per period.

Given that:

The interest is compounded yearly, i.e n = 1, for 1 year, t = 1, the compound interest is Rs 450 i.e A = 450. Therefore:

450=P(1+\frac{r}{1} )^{1*1}=P(1+r)\\450=P(1+r).\ .\ .\ (1)

For 2 year, t = 2, the compound interest is Rs 945 i.e A = 945. Therefore:

945=P(1+\frac{r}{1} )^{1*2}=P(1+r)^2\\945=P(1+r)^2.\ .\ .\ (2)

Dividing equation 2 by equation 1 gives:

2.1 = 1 + r

r = 2.1 - 1 = 1.1

r = 1.1

Put r = 1.1 in 450 = P(1 + r)

450 = P(1 + 1.1)

450 = 1.11P

P = 405.4

Therefore the rate is 1.1 = 110% and P = Rs 405.4

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Step-by-step explanation:

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Answer: x=1.5811389999999999 , or 1.59

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