If and only if it is a proportional relationship, the problem can be solved by creating a proportion of B1/T1=B2/T2. This can also be expressed as 4.5/3.5=5.4/x given the values. You must cross multiply, so 4.5x=3.5(5.4). This simplifies to x=4.2. So, the tail length would be 4.2 feet.
Hope this helps.
Answer:
The number of half-page advertisements is 4.
The number of Full-page advertisements is 11.
Step-by-step explanation:
According to the Question,
- Given, An advertising company charges $60 per half-page advertisement and $100 per full-page advertisement. Michael has a budget of $1340 to purchase 15 advertisements.
Let, 'x' be the number of half-page advertisements and 'y' be the number of full-page advertisements.
- Thus, 60x + 100y is the money charged, and given that he has a budget of $ 1340.
60x + 100y = 1340
- And, the number of advertisements is 15. So, the other equation is
x + y = 15
Now, We have Two Equations,
60x + 100y = 1340 and x + y = 15
- the solution of the system is Put x=(15-y) in Equation 60x + 100y = 1340
60 (15-y) + 100y = 1340
900 - 60y + 100y = 1340
40y = 1340 - 900
40y = 440
y = 440/40
y = 11 So, For x = 15 - y ⇒ 15-11 ⇒ x=4 .
- Thus, the number of half-page advertisements is 4 and The number of Full-page advertisements is 11 .
Answer:
Step-by-step explanation:
GH bisects ∠FGI
∠HGI = ∠HGF
4x - 14 = 3x - 3
4x = 3x - 3 + 14 {Add 14 to both sides}
4x = 3x + 11 {Subtract 3x from both sides}
4x - 3x = 11
x = 11
∠HGI = 4x - 14
= 4*11 - 14
= 44 - 14
= 30°
∠FGI = 30 + 30
= 60°
5(b - 0.18b).....use the distributive property
5b - 0.90b <== ur equivalent expression
Mary bought 4 apples at $8
so unit price = 8/4 = $2/each
Table:
Apples Price
1 $2
3 $6
4 $8
7 $14
