A boy pulls his 9.0 kg sled, applying a horizontal force of 14.0 N (rightward). The coefficient of friction between the snow and
1 answer:
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Answer:
Explanation:
attached is the solution
Answer:
a) 0.477 W/m²
b) 13.407 N/C
c) 18.96 N/C
Explanation:
P = Power = 150 W
r = Distance = 5 m
ε₀ = Permittivity of space = 8.854×10⁻¹² F/m
a) Average intensity
∴ Average intensity is 0.477 W/m²
b) Rms value
∴ Rms value of the electric field is 13.407 N/C
c) Peak value
∴ Peak value of the electric field is 18.96 N/C
Answer:
Explanation:
mass, m = 12 kg
Force, F = 40 N
θ = 37° below the horizontal
(a)
Diagram is attached
(b) Let N be the normal reaction
According to the diagram
N + F Sin θ = m g
N = mg - F Sin θ
N = 12 x 9.8 - 40 x Sin 37
N = 117.6 - 24.07
N = 93.53
