Answer:
conduction electrons
Explanation:
Metallic bonding is a type of chemical bonding that rises from the electrostatic attractive force between conduction electrons and positively charged metal ions. It may be described as the sharing of free electrons among a structure of positively charged ions.
the answer is correct why.
EXPLANATION:
First copy the 15 and u will × now in the no. of (9.8 ×1.5) the equal is 15 m/s -14.7m/s so we - the now the 15-14.7 and the ANSWER IS 0.3m/s.
Explanation:
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<em>D</em><em>O</em><em>N</em><em>T</em><em> </em><em>F</em><em>O</em><em>R</em><em>G</em><em>E</em><em>T</em><em> </em><em>M</em><em>A</em><em>'</em><em>R</em><em>K</em><em> </em><em>M</em><em>E</em><em> </em><em>A</em><em>S</em><em> </em><em>A</em><em> </em><em>B</em><em>R</em><em>I</em><em>N</em><em>L</em><em>I</em><em>S</em><em>T</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>F</em><em>O</em><em>L</em><em>L</em><em>O</em><em>W</em><em> </em><em>M</em><em>E</em>
Orbits only exist because of gravity.
If gravity somehow suddenly shuts off, then an object
in an orbit sails away in a straight line, in the direction
and at the speed it had when gravity disappeared.
<span>(6.0x10^-22, -1.40x10^-21, 0) kg*m/s
Momentum is a conserved quantity. The total momentum of the system before and after the interactions will not change. So, let's look at the momentum before the interaction.
(3.2x10^-21, 0, 0) kg*m/s and (0,0,0) kg*m/s
After the interaction
(2.6x10^-21, 1.40x10^-21, 0) kg*m/s
and the other proton has to have a momentum that when added to this momentum equal the original value. Since the y and z vectors were initially 0, all we need for the y and x vector values of the result is to negate them. The x vector value will be
3.2x10^-21 - 2.6x10^-21 = 0.6x10^21 = 6.0x10^-22. So the other proton will have a momentum of
(6.0x10^-22, -1.40x10^-21, 0) kg*m/s</span>
Answer:
effective dose is 1.2 mrem
Explanation:
given data
mass m = 70 kg
absorb n = 4.5 × 
energy = 1.2 MeV
neutrons = 10
to find out
equivalent dosage
solution
we know here total energy in a day is
total energy = 4.5 × × 1.2
total energy = 5.4 × 
eV
and total energy = 5.4 × × 1.6 × 
so total energy = 8.64 × 
J
and for mass 70 kg
it will be = 8.64 × / 70
= 1.23 × 
rad
so
effective dose is here = 1.23 × × 10 = 0.0012 rem
so effective dose is 1.2 mrem
