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yulyashka [42]
4 years ago
11

Why is moon is non-lomis back​

Physics
1 answer:
qwelly [4]4 years ago
4 0

Explanation:

At night, when that part of Earth is facing away from the sun, space looks black because there 8s no nearby bright source of light like the sun , to be scattered

You might be interested in
Calculate the density of a material that has a bat a mass of 52.457 g any volume of 13.5 cm³
3241004551 [841]
Answer:
d = 3.8857 g/cm^3

Explain:
Formula/: d = m/V

Hope this helps!
(a brainliest would be appreciated)
4 0
3 years ago
A projectile is fired with an initial speed of 40 m/s at an angle of elevation of 30∘. Find the following: (Assume air resistanc
BabaBlast [244]

Answer:

a. 2.0secs

b. 20.4m

c. 4.0secs

d. 141.2m

e. 40m/s, ∅= -30°

Explanation:

The following Data are giving

Initial speed U=40m/s

angle of elevation,∅=30°

a. the expression for the time to attain the maximum height is expressed as

t=\frac{usin\alpha }{g}

where g is the acceleration due to gravity, and the value is 9.81m/s if we substitute values we arrive at

t=40sin30/9.81\\t=2.0secs

b. the expression for the maximum height is expressed as

H=\frac{u^{2}sin^{2}\alpha  }{2g} \\H=\frac{40^{2}0.25 }{2*9.81} \\H=20.4m

c. The time to hit the ground is the total time of flight which is twice the time to reach the maximum height ,

Hence T=2t

T=2*2.0

T=4.0secs

d. The range of the projectile is expressed as

R=\frac{U^{2}sin2\alpha}{g}\\R=\frac{40^{2}sin60}{9.81}\\R=141.2m

e. The landing speed is the same as the initial projected speed but in opposite direction

Hence the landing speed is 40m/s at angle of -30°

3 0
3 years ago
Two small insulating spheres with radius 3.50×10−2 m are separated by a large center-to-center distance of 0.555 m. One sphere i
xz_007 [3.2K]

Answer:

E = 7.83 \times 10^5 N/C

Explanation:

Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point

So we know that

E = \frac{kq_1}{r^2} + \frac{kq_2}{r^2}

here we know that

q_1 = 4.20 \mu C

q_2 = 2.50 \mu C

r = \frac{0.555}{2}

so we have

E = \frac{(9\times 10^9)(4.20 + 2.50) \times 10^{-6}}{0.2775^2}

E = 7.83 \times 10^5 N/C

4 0
3 years ago
Explain how the information from stimuli can become a memory or result in a behavior.
Natali [406]

Answer:

Potentiation, habituation, and sensitization are three ways in which stimuli in the environment produce changes in the nervous system.

5 0
3 years ago
A 1. 30 kg block slides with a speed of 0. 855 m/s on a frictionless horizontal surface until it encounters a spring with a forc
boyakko [2]

a) For 0 compressions:

potential energy = U =  0 J

kinetic energy = k = 0.383 J

total mechanical energy = E = 0.383 J

b) For compression of 1 cm:

potential energy = U = 0.0228 J

kinetic energy = k = 0.155 J

total mechanical energy = E = 0.383 J

c) For compression of 2 cm :

potential energy = U = 0.1104 J

kinetic energy = k = 0.272 J

total mechanical energy = E = 0.383 J

d) For compression of 3cm:

potential energy  = U = 0.248 J

kinetic energy = k = 0.177 J

total mechanical energy = E = 0.383 J

<h3>Method for solving:</h3>

The equations for kinetic energy is:

k= 1/2*m*v^{2}

The equation for elastic potential energy is:

U= 1/2*ks*x^{2}

Where,

m= mass of the block

v= velocity

ks= spring constant

x= displacement of the spring

(a)when compression= 0 cm

U= 1/2*ks*v{2}

U= 1/2*552*(0)^{2}

 = 0 J

Kinetic energy:

k= 1/2*m*x^{2}

k= 1/2*(1.05)*(0.855)^{2}

k= 0.383 J

Mechanical energy:

E= k + U

E= 0.383+0

E= 0.383 J

There will be no work done by friction or any other dissipative force, hence this energy will be conserved, or it will remain constant (like air resistance). This indicates that only spring potential energy will be created from the kinetic energy (there is no thermal energy due to friction, for example).

(b) spring potential = ?

U= 1/2* 457 N/m*(0.01)^{2}

U= 0.0228 J

Since the mechanical energy must remain constant, we may calculate the kinetic energy using the mechanical energy equation:

E= k + U

0.383= k + 0.0228

k= 0.383 - 0.228

k= 0.155

(c)spring constant when x= 0.02

U= 1/2*552*(0.02)^{2}

U= 0.1104 J

Using the equation of mechanical energy:

E= k +U

0.383= k+ 0.1104

k= 0.383 - 0.1104

k= 0.272 J

(d) U= 1/2*552*(0.03)^{2}

U= 0.2484 J

E= 0.383 J

k = E - U

k= 0.383- 0.206

k= 0.177

To learn more about spring potential energy visit:

brainly.com/question/28168175

#SPJ4

3 0
2 years ago
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