PLEASE HELP ME!!!!!!!!

1 answer:

3 0

Angle θ between two vectors is given by, $\theta =cos^{-1}( \frac{u
 \cdot v}{|u||v|} )$ ; where $u \cdot 
v=-5(-4)+(-4)(-3)=20+12=32$ ; $|u|= \sqrt{ (-5)^{2} + (-4)^{2} } = 
\sqrt{25+16} = \sqrt{41}$ and $|v|=\sqrt{ (-4)^{2} + (-3)^{2} } = 
\sqrt{16+9} = \sqrt{25}=5$ .
Therefore, $\theta =cos^{-1}( \frac{32}{ 5\sqrt{41}} )=cos^{-1}0.9995=1.8^o$

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