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sergey [27]
3 years ago
14

PLEASE HELP ME!!!!!!!! 

Mathematics
1 answer:
Delicious77 [7]3 years ago
3 0
Angle θ between two vectors is given by, \theta =cos^{-1}( \frac{u
 \cdot v}{|u||v|} ); where u \cdot 
v=-5(-4)+(-4)(-3)=20+12=32; |u|= \sqrt{ (-5)^{2} + (-4)^{2} } = 
\sqrt{25+16} = \sqrt{41} and |v|=\sqrt{ (-4)^{2} + (-3)^{2} } = 
\sqrt{16+9} = \sqrt{25}=5.
Therefore, \theta =cos^{-1}( \frac{32}{ 5\sqrt{41}} )=cos^{-1}0.9995=1.8^o
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