Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
The interior angles next to the 2h angles are congruent and each one measures 70 degrees. Since the interior angle is 70 degrees the exterior angle is 110 degrees.
2h = 110
divide both sides by 2
h = 55
This is an answer should help you
Answer:
0.01190476, but since you have to round to the nearest hundredth your answer should be 0.01
Step-by-step explanation:
Answer:
Slope = 5
Point = (4, 2)
Step-by-step explanation:
