Answer: Intersection of A and B = 2
Step-by-step explanation:
Total cards = 52
Let A is the event of drawing a 6 from the deck, and B is the event of drawing a black playing card from the deck.
Total cards having 6 on them = 4
[There are 4 suits of two different colors red and black.]
Total black playing card =26
Intersection of A and B = Black cards having 6 = 2
hence, Intersection of A and B = 2
The correct question is
<span>Given cos theta=4/9 and csc theta < 0 find sin theta and tan theta
</span>
we know that
csc theta=1/sin theta
if csc theta < 0
then
sin theta < 0
we have that
<span>cos theta=4/9
we know that
sin</span>² theta+cos² theta=1
so
sin² theta=1-cos² theta-----> 1-(4/9)²----> 1-(16/81)----> 65/81
sin theta=-√(65/81)---->-√65/9
the answer Part a) is
sin theta=-√65/9
Part b) find tan theta
tan theta=sin theta/cos theta
tan theta=(-√65/9)/(4/9)-----> tan theta=-√65/4
the answer part b) is
tan theta=-√65/4
1) Two triangles are similar if they have congruent angles and proportional sides (for each corresponding leg).
2) So let's check whether there are similar triangles by setting a proportion:
3) So yes they are similar, i.e. ΔCAB ~ΔHGJ
Answer:
Um ig... which problem?
Step-by-step explanation:
Subtract five to both sides then subtract 2 to both sides then dived your y
