All categories

3 years ago

Sedimentary rock _____ to form sediment.

Chemistry

2 answers:

harina [27]3 years ago

4 0

Answer: B. weathers

Explanation:

Sedimentary rocks are the rocks that are formed by the accumulation of small particles also called as sediments. These rocks are formed by the compaction or cementation of organic and inorganic particles coming from the animals, plant source and weathering of other parent rocks, organic particles from the oceanic floors all contributes to the formation of the sedimentary rocks.

The sedimentary rock weathers to form the sediments. These rocks can come in contact of high speed wind currents, water or any other agent which can distort or disintegrate these rocks into sediments by the process of weathering.

Rom4ik [11]3 years ago

3 0

Weathers. is the answer

You might be interested in

Which element has the highest (most negative) electron affinity? kr br k be?

Ratling [72]

The element would be Br

7 0

4 years ago

What is the volume (in cubic inches) of 3.6 lb of titanium?

Monica [59]

Answer:

22 cubic inches

Explanation:

We are given;

Mass of titanium = 3.6 pounds

We are required to determine the volume of titanium in cubic inches

We need to know the density of titanium;

Density of titanium = 4.51 g/cm^3

1 pound = 453.592 g

therefore, 3.6 pound = (3.6 × 453.592 g per pound)

= 1632.93 g

Therefore;

Volume = Mass ÷ density

= 1632.93 g ÷ 4.51 g/cm^3

= 362.069 cm³

But, 1 in³ = 16.387 cm³

Therefore;

Volume = 362.069 cm³ ÷ 16.387 cm³ per in³

= 22.095 in³

= 22 in³

Thus the volume of titanium is 22 cubic inches

8 0

3 years ago

Vaporized water is also known as

viva [34]

Answer:

fog

Explanation:

4 0

3 years ago

Worksheet Ch.3: % Composition, Molarity, and Other Units for

Ann [662]

The percentage composition by mass of the elements in the compound are:

Ai. The percentage composition by mass of Na in 3.65 g of NaF is 54.8%

Aii. The percentage composition by mass of F in 3.65 g of NaF is 45.2%

Bi. The percentage composition by mass of Zinc in the compound is 67.1%

Bii. The percentage composition by mass of Sulfur in the compound is 32.9%

Percentage composition by mass of an element in a compound can be obtained by using the following formula: $Percentage = \frac{mass of Element}{mass of compound} * 100$

Ai. Determination of the percentage of Na in 3.65 g of NaF

Mass of Na = 2 g

Mass of NaF = 3.65 g

<h3>Percentage of Na =? </h3>

$Percentage = \frac{mass of element }{mass of compound} * 100\\\\Percentage of Na = \frac{2}{3.65} * 100$

<h3>Percentage of Na = 54.8%</h3>

Aii. Determination of the percentage of F in 3.65 g of NaF

Mass of F = 1.65 g

Mass of NaF = 3.65 g

<h3>Percentage of F =? </h3>

$Percentage = \frac{mass of element }{mass of compound } * 100\\\\Percentage of F = \frac{1.65}{3.65} * 100\\\\$

<h3>Percentage of F = 45.2%</h3>

Bi. Determination of the percentage composition of Zn in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

<h3>Percentage of Zn =? </h3>

$Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of Zn = \frac{32.69}{48.72} *100\\\\$

<h3>Percentage of Zn = 67.1%</h3>

Bii. Determination of the percentage composition of Sulphur in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

Mass of S = 48.72 – 32.69 g

Mass of S = 16.03 g

<h3>Percentage of S =? </h3>

$Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of S = \frac{16.03}{48.72} * 100\\\\$

<h3>Percentage of S = 32.9%</h3>

Learn more: brainly.com/question/1350382

3 0

3 years ago

Identify each of the following as an example of either basic research, applied research, or

zvonat [6]

Answer:

A) a new type of refrigerant that is less damaging to the environment is developed. Applied development

B) a new element is synthesized in a particle accelerator. Basic development.

C) a computer is redesigned to increase the speed of the computer. Technological development.

Explanation:

8 0

3 years ago